Question

public class FooCorporation {

    public static void main(String[] args) {
        System.out.println("Employee 1:");
        payment(7.5,35);
        System.out.println("Employee 2:");
        payment(8.2, 47);
        System.out.println("Employee 3:");
        payment(10.00,73);
    }

    public static void payment(double basePay, int hours) {
        if(basePay<8. || hours >60) {
            System.out.println("ERORR; base pay less than 8.00$ or hours worked greater than 60.");
    }

        else if(hours<=40) {
                System.out.println("Total pay = " + hours*basePay + "$");
            }
            else if(hours>40) {
                int count = hours-40;
                System.out.println("Total pay = " + (hours-count)*basePay+(1.5*basePay*count)+ "$");

            }
        }
}

为什么员工2的输出错误？

GIVEN : BasePay HoursWorked
Employee 1 $7.50 35 
Employee 2 $8.20 47 
Employee 3 $10.00 73

Answer 1

当你在这里打印时：

System.out.println("Total pay = " + (hours-count)*basePay+(1.5*basePay*count)+ "$");

您正在连接2个数字（(hours-count)*basePay和(1.5*basePay*count)），而不是以数学方式添加它们。您需要将其替换为（在括号中添加数字）：

System.out.println("Total pay = " + ((hours - count) * basePay + (1.5 * basePay * count)) + "$");

原因是首先评估"Total pay = " + (hours-count)*basePay，并将表达式(hours-count)*basePay的结果连接到字符串Total pay =。接下来，此连接的结果与表达式(1.5 * basePay * count)的结果连接在一起。由于您不需要这个，并且您希望在连接之前先评估两个表达式，因此需要用括号括起它们以使其优先。

Answer 2

使用 System.out.println（“总薪水=”+（（小时数）* basePay +（1.5 * basePay * count）））;

需要添加大括号，以便JVM知道需要处理语句的顺序

输出错误_

2 个答案: