Question

我有一个需要修改的shell脚本，以返回带有相关用户ID的全名。我真的可以使用帮助详细解释如何使用正确的语法正确修改此shell脚本。如果有人可以帮助我了解如何完成这项任务，我将非常感谢您提供的任何帮助。我在这里学习，我对这个社区很新，所以如果发布错误或格式错误，请让我知道我做错了什么。提前致谢

这是所需的输出：

$ ./findName.sh eiei

SETSUNA F SEIEI

$

下面是shell脚本本身。文件/ acct / commmon / spring-names是所有用户ID和全名所在的位置。

#!/bin/sh
# findName.sh 


if [ $# -eq 1 ]; then
# if there is exactly one command line arg used with the command
# do something(s).
echo "Your command line entry is: $1" > test
if [ -s ./test ]; then
cat test
else
    echo "You should not see this line as output....."
fi
else

# tell the user how to use the command and exit the script
echo "usage: `basename $0` [only_one_argument]"
exit 1

Answer 1

我不确定我是否理解你想要做什么，但我认为你想用$ 1 arg运行一个脚本./findName.sh。然后该脚本将获得$ 1并在文件中搜索名称？如果我错了请纠正我，我会更新我的答案。因为你有bash标记，我做了shebang line bash。

ORIGINAL：

#!/bin/sh
# findName.sh 


if [ $# -eq 1 ]; then
# if there is exactly one command line arg used with the command
# do something(s).
echo "Your command line entry is: $1" > test
if [ -s ./test ]; then
cat test
else
    echo "You should not see this line as output....."
fi
else

# tell the user how to use the command and exit the script
echo "usage: `basename $0` [only_one_argument]"
exit 1

REVISION：

#!/bin/bash
# findName.sh
searchFile="/acct/commmon/spring-names"

if [[ $1 = "" ]] ; then
  echo "You need to supply an argument to the script. Please rerun the script. syntax is below."
  echo "./`basename $0` john"
  exit 2
fi

grep -i $1 ${searchFile}
if [[ $? = "1" ]] ; then
  echo "$1 was not found in ${searchFile}"
fi

出口

Answer 2

给定

的文件格式

First,Middle,Last,Userid

以下应该做你想要的。阅读内联评论以获取更多详细信息：

#!/bin/bash
# findName.sh
searchFile="/acct/common/spring-names"

if [[ $1 = "" ]] ; then
  echo "You need to supply an argument to the script. Please rerun the script. syntax is below."
  echo "./`basename $0` john"
  exit 2
fi

# read the file line by line
while read LINE
do
    # file format: First,Middle,Last,Userid
    # set the index values based on the line format given above, change as needed.
    firstNameIndex=0
    middleNameIndex=1
    lastNameIndex=2
    userIDIndex=3

    # read the line into an array
    IFS=', ' read -r -a lineArray <<< "$LINE"

    # if the passed parameter equals the value of the line at userIDIndex 
    if [[ $1 -eq ${lineArray[$userIDIndex]} ]] ; then
        echo ${lineArray[$firstNameIndex]} ${lineArray[$middleNameIndex]} ${lineArray[$lastNameIndex]}
        exit 1 # this assumes only one instance of a user id per file, if you expect more, than delete this line.
    fi

done < "$searchFile"

您可以将它们存储在变量中以便稍后进行更多操作，而不是像在此处所做的那样回显数组值，例如

firstName=${lineArray[$firstNameIndex]}
middleName=${lineArray[$middleNameIndex]}
lastName=${lineArray[$lastNameIndex]}

给定具有以下内容的文件：

Hunter,David,Hatch,hhatch

输出结果为：

$ ./findName.sh hhatch
Hunter David Hatch

修改shell脚本以返回与正确用户ID

2 个答案: