具有关联表格的内连接总是以＆＃34;与＆＃34;错误

Question

我想进行此查询（此处$ownerQuery是相关部分）：

$searchQuery = $this->Tickets
            ->find('byStatus',['status' =>$status])
            ->find('byTitle',['queries' => $queries]);
$ownerQuery = $searchQuery
            ->innerJoinWith(
                'Projects.ProjectsTickets', function($q) use( &$userId){
                    return $q->where(['Tickets.id' => 'ProjectsTickets.ticket_id'])
                             ->where(['Projects.id' => 'ProjectsTickets.project_id'])
                             ->where(['Projects.user_id' => $userId]);
                }
             );

或者达到相同效果的东西，但是我尝试过的每一个变体最终都与错误无关。

以下是我的协会：

ProjectsTicketsTable：

class ProjectsTicketsTable extends Table
{
public function initialize(array $config)
    {
        parent::initialize($config);

        $this->table('projects_tickets');
        $this->displayField('project_id');
        $this->primaryKey(['project_id', 'ticket_id']);

        //$this->belongsTo('Projects', [
        //    'foreignKey' => 'project_id',
        //    'joinType' => 'INNER'
        //]);
        //$this->belongsTo('Tickets', [
        //    'foreignKey' => 'ticket_id',
        //    'joinType' => 'INNER'
        //]);

        $this->belongsTo('Projects');
        $this->belongsTo('Users');
    }
}

ProjectsTable：

class ProjectsTable extends Table
{
    public function initialize(array $config)
    {
        parent::initialize($config);

        $this->table('projects');
        $this->displayField('title');
        $this->primaryKey('id');

        $this->addBehavior('Timestamp');

        $this->belongsTo('Users', [
            'foreignKey' => 'user_id',
            'joinType' => 'INNER'
        ]);
        $this->belongsTo('Tags', [
            'foreignKey' => 'tag_id',
            'joinType' => 'INNER'
        ]);
        //$this->belongsToMany('Tickets', [
        //    'foreignKey' => 'project_id',
        //    'targetForeignKey' => 'ticket_id',
        //    'joinTable' => 'projects_tickets'
        //]);
        $this->belongsToMany('Tickets', [
            'through' => 'ProjectTickets',
        ]);
        $this->belongsToMany('Users', [
            'foreignKey' => 'project_id',
            'targetForeignKey' => 'user_id',
            'joinTable' => 'projects_users'
        ]);
    }
}

TicketsTable：

class TicketsTable extends Table
{
public function initialize(array $config)
    {
        parent::initialize($config);

        $this->table('tickets');
        $this->displayField('title');
        $this->primaryKey('id');

        $this->addBehavior('Timestamp');

        //$this->belongsToMany('Projects', [
        //    'foreignKey' => 'ticket_id',
        //    'targetForeignKey' => 'project_id',
        //    'joinTable' => 'projects_tickets'
        //]);
        $this->belongsToMany('Projects', [
            'through' => 'ProjectTickets',
        ]);
        $this->belongsToMany('Comments', [
            'foreignKey' => 'ticket_id',
            'targetForeignKey' => 'comment_id',
            'joinTable' => 'tickets_comments'
        ]);
        $this->belongsToMany('Users', [
            'foreignKey' => 'ticket_id',
            'targetForeignKey' => 'user_id',
            'joinTable' => 'tickets_users'
        ]);
    }
}

我能解决的关联或查询是否有问题？

编辑：通过更改提供的链接NDM，我确实设法摆脱了“无关联错误”。但是，尝试组合表中列的所有查询总是会产生0结果。

例如，应该返回所有故障单的搜索（因为所有故障单都在ProjectsTickets表中）都没有返回任何内容：

$ownerQuery = $searchQuery
            ->innerJoinWith(
                'Projects.ProjectsTickets', function($q) use( &$userId){
                    return $q->where(['Tickets.id' => 'ProjectsTickets.ticket_id']);
                             //->where(['Projects.id' => 'ProjectsTickets.project_id'])
                             //->where(['Projects.user_id' => $userId]);
                }
             );

但是，如果我只取消注释用户线，则它正确显示所有结果。

编辑2：虽然关联解决方法有效但匹配的解决方案并不会有问题。例如，如果我想进行此查询而不必在Tickets和ProjectsUsers之间建立关联：

    $adminQuery = $searchQuery
        ->distinct()
        ->matching('ProjectsUsers')
        ->where([
                'Tickets.id = ProjectsTickets.ticket_id',
                'ProjectsTickets.project_id = ProjectsUsers.project_id',
                'ProjectsUsers.user_id' => $userId,
                'ProjectsUsers.role = Admin'
            ]);

这仍然导致Tickets is not associated with ProjectsUsers