Question

我需要向shell发送命令“MYSHELL＆gt;”在它开始之后。

prcs = subprocess.Popen("MYSHELL; cmnd1; cmnd2;",shell=True,
subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

outputPrcs, err =  prcs.communicate()
print outputPrcs

仅实现进入shell的问题，不发送其他命令（cmnd1; cmnd2;）。

结果： MYSHELL＆GT;

Answer 1

来自docs：

communicate(self, input=None)
   Interact with process: Send data to stdin.  Read data from
   stdout and stderr, until end-of-file is reached.  Wait for
   process to terminate.  The optional input argument should be a
   string to be sent to the child process, or None, if no data
   should be sent to the child.

注意，Wait for process to terminate.我认为您需要的是pexpect。它不在标准库中，但它会做你想要的。

示例：

import pexpect

process = pexpect.spawn("python")
process.expect_exact(">>> ")
process.sendline('print("It works")')
process.expect("\n.*\n")
response = process.after.strip()
print(response)

输出：

It works

Answer 2

如果要将输入发送到shell，则应将其作为communicate中的参数传递，如下所示：

prcs = subprocess.Popen("MYSHELL",shell=True,
subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

outputPrcs, err =  prcs.communicate("cmnd1; cmnd2;")
print outputPrcs

试验：

>>> from subprocess import *
>>> p = Popen("python", shell=True, stdin=PIPE, stdout=PIPE, stderr=PIPE)
>>> o,e = p.communicate("print 'it works'")
>>> print o
it works

>>>

Answer 3

它将工作@Ahmed。在Linux上尝试以下代码：

value

使用Python将命令发送到子shell

3 个答案: