JTable选择并取消选择不工作

时间:2016-02-09 10:03:26

标签: java swing jtable

我的JTable有问题。首先,我在表格中选择了一些条目。但是,当我取消选择其中一些时,表格无法理解。

示例场景:在我改变主意并取消选择job2后,我选择了job1和2进行测试。但在结果中我看到job1 job1和job2(作业1见过2次,即使我取消选择作业2,我看到了它们。)或者在选择了所有作业(选择所有按钮)之后我想取消全部作业(清除)按钮)当我点击清除所有表似乎是空的。这很好,但不知何故,该计划的背景仍然保护所有旧的选择。我该如何解决这个问题?

尝试:

我通过读取csv文件创建了我的表行。

public class JobSelectionListPanel extends JPanel {

  private static final long serialVersionUID = 5198916547962359735L;

  private static JobSelectionListPanel INSTANCE = new JobSelectionListPanel();

  public static JobSelectionListPanel getInstance() {
    return INSTANCE;
  }

  private JTable table;
  private JButton next, back, btnClear, btnNewButton, btnChooseAll;
  private JobList fnnJobList = new JobList();

  private JobSelectionListPanel() {

    table = new JTable();
    JScrollPane scrollPane = new JScrollPane(table);
    table.setBorder(new CompoundBorder());

    // Read all FNN jobs from file
    try {
      fnnJobList.readFromFile("rules.csv");
    } catch (IOException e1) {
      System.out.println("You are not able to read the rules.csv file");
    }

    // Create ArrayList of JobNames



      Object[][] initialData = new Object[fnnJobList.size()][1];

        int i = 0;
        for (Job jobDes : fnnJobList) {
          initialData[i][0] = (Object) jobDes.getJobname();
          i++;
        }

        String[] columnNames = new String[] { "", "Your preferences" };
        table.setModel(new DefaultTableModel(initialData, columnNames) {

          private static final long serialVersionUID = 1L;
          @SuppressWarnings("rawtypes")
          Class[] columnTypes = new Class[] { Object.class, Boolean.class };

          @SuppressWarnings({ "unchecked", "rawtypes" })
          public Class getColumnClass(int columnIndex) {
            return columnTypes[columnIndex];
          }
        });

        table.getColumnModel().getColumn(1).setPreferredWidth(80);
        table.getColumnModel().getColumn(1).setMinWidth(40);
        table.setSelectionMode(ListSelectionModel.MULTIPLE_INTERVAL_SELECTION);
        table.setCellSelectionEnabled(true);

我想要选择所有行,然后我实现了这个。 btnChooseAll =新的JButton(“全选”);

btnChooseAll.addActionListener(new ActionListener() {
  public void actionPerformed(ActionEvent e) {

    DefaultTableModel chooseAllData = (DefaultTableModel) table.getModel();
    if (DeviceGroups.DeviceAList.size() == 0 || DeviceGroups.DeviceBList.size() == 0
        || DeviceGroups.DeviceCList.size() == 0 || DeviceGroups.DeviceDList.size() == 0)
      JOptionPane.showMessageDialog(null,
          "You should choose at least 1 device for each test device to apply this test case", "Invalid OPTION",
          JOptionPane.ERROR_MESSAGE);
    else
      for (int i = 0; i < chooseAllData.getRowCount(); i++) {
        for (int j = 1; j < chooseAllData.getColumnCount(); j++) {
          chooseAllData.setValueAt(true, i, j);

        }
      }

  }
});

清除所有偏好:

 btnClear = new JButton("Clear all");
    // Clear button create a model of JTable and delete all the rows of table!!
    btnClear.addActionListener(new ActionListener() {
      public void actionPerformed(ActionEvent e) {

        DefaultTableModel clearTableData = (DefaultTableModel) table.getModel();
        for (int i = 0; i < clearTableData.getRowCount(); i++) {
          for (int j = 1; j < clearTableData.getColumnCount(); j++) {
            clearTableData.setValueAt(null, i, j);

          }
        }
      }
    });

1 个答案:

答案 0 :(得分:3)

我在您的代码中看到以下问题:混合视图索引和模型索引。这是令人讨厌的片段:

i

您正在使用table.getValueAt(i, 1) != null变量来表示视图行索引,因为您正在检查此语句中的值:i

但是稍后您使用String jobName = ((DefaultTableModel) table.getModel()).getValueAt(i, 0).toString(); 来索引模型:

i

如果 String jobName = ((DefaultTableModel) table.getModel()).getValueAt(table.convertRowIndexToModel(i), 0).toString(); 是视图索引,则需要在索引模型之前将其转换为模型索引:

table.getValueAt(i, 1) != null

此外,当在视图中切换列时(即在GUI中的屏幕上),以下内容可能无法按预期工作:

table.getValueAt(i, table.convertColumnIndexToView(1)) != null

您很可能意味着,在模型中获取第二列值,而不是视图。最佳重写然后

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