Question

我正在尝试解析json但是它给了我错误java lang.string无法转换为jsonArray。这是我的json和错误：

Value {"MemberList":[{"MemberId":1,"FirmId":1,"MemberTypeId":1,
"MemberUserName":"test@example.com",      "MemberName":"sth","UpdateDate":"\/Date(1421840040000)\/",
"LastLoginDate":"\/Date(1454995980000)\/",
"FirmTypeId":1,"FirmName":"Firm","FirmOfficialName":"Firm",
"FirmRowGuid":"sth","MemberRowGuid":"sth","AuthToken":"sth",
"IsRegistered":1}],"MemberPageList":null,"FirmModuleList":null,"Status":true,
"StatusCode":"OK"} of type java.lang.String cannot be converted to JSONArray

当我删除MemberList标头并手动运行它工作正常，但我必须用标头解析它我应该如何解析它。 userDetail是我的json字符串：

JSONArray jsonArray = new JSONArray(userDetail);
                    member = new Member();
                    for (int i = 0; i < jsonArray.length(); i++) {

                    JSONObject jsonObject = jsonArray.getJSONObject(i);
                    member.MemberId = jsonObject.optInt("MemberId");
                    member.MemberTypeId = jsonObject.optInt("MemberTypeId");
                    member.FirmTypeId = jsonObject.optInt("FirmTypeId");
                    member.IsRegistered = jsonObject.optInt("IsRegistered");

                    member.MemberUserName = jsonObject.optString("MemberUserName");
                    member.MemberName = jsonObject.optString("MemberName");
                    member.UpdateDate = jsonObject.optString("UpdateDate");
                    member.LastLoginDate = jsonObject.optString("LastLoginDate");
                    member.FirmName = jsonObject.optString("FirmName");
                    member.FirmOfficialName = jsonObject.optString("FirmOfficialName");
                    member.FirmRowGuid = jsonObject.optString("FirmRowGuid");
                    member.MemberRowGuid = jsonObject.optString("MemberRowGuid");
                    member.AuthToken = jsonObject.optString("AuthToken");
                }

Answer 1

它的json对象不是数组，所以改变，

JSONArray jsonArray = new JSONArray(userDetail);

到

JSONObject jsonObj= new JSONObject(userDetail);
JSONArray jsonArray = jsonObj.getJSONArray("MemberList");

要手动检查json，请使用此http://jsoneditoronline.org/

CODE：

    JSONObject jsonObj= new JSONObject(userDetail);
    JSONArray jsonArray = jsonObj.getJSONArray("MemberList");

                    for (int i = 0; i < jsonArray.length(); i++) {
                    member = new Member();
                    JSONObject jsonObject = jsonArray.getJSONObject(i);
                    member.MemberId = jsonObject.optInt("MemberId");
                    member.MemberTypeId = jsonObject.optInt("MemberTypeId");
                    member.FirmTypeId = jsonObject.optInt("FirmTypeId");
                    member.IsRegistered = jsonObject.optInt("IsRegistered");

                    member.MemberUserName = jsonObject.optString("MemberUserName");
                    member.MemberName = jsonObject.optString("MemberName");
                    member.UpdateDate = jsonObject.optString("UpdateDate");
                    member.LastLoginDate = jsonObject.optString("LastLoginDate");
                    member.FirmName = jsonObject.optString("FirmName");
                    member.FirmOfficialName = jsonObject.optString("FirmOfficialName");
                    member.FirmRowGuid = jsonObject.optString("FirmRowGuid");
                    member.MemberRowGuid = jsonObject.optString("MemberRowGuid");
                    member.AuthToken = jsonObject.optString("AuthToken");
                }

Answer 2

{
"MemberList": [{
    "MemberId": 1,
    "FirmId": 1,
    "MemberTypeId": 1,
    "MemberUserName": "test@example.com",
    "MemberName": "sth",
    "UpdateDate": "\/Date(1421840040000)\/",
    "LastLoginDate": "\/Date(1454995980000)\/",
    "FirmTypeId": 1,
    "FirmName": "Firm",
    "FirmOfficialName": "Firm",
    "FirmRowGuid": "sth",
    "MemberRowGuid": "sth",
    "AuthToken": "sth",
    "IsRegistered": 1
}],
"MemberPageList": null,
"FirmModuleList": null,
"Status": true,
"StatusCode": "OK"

}

因为你可以看到我们作为一个对象得到的顶级根数据，在这个对象中我们得到＆＃34; MemberList＆＃34;的数组，所以你需要先获取对象然后在其中获取数组。

并执行此操作以将响应转换为String

HttpResponse response=client.execute(post);
String obj= EntityUtils.toString(response.getEntity());

然后根据需要使用它。

希望你能得到这个。

如何在json中解析对象？

2 个答案: