即使使用GROUP BY CLAUSE也能显示所有结果

Question

查询： 如何按月分类？

select format(datee,'mmm-yyyy') as [Months],sum(amount) as Amount 
from ledger_broker 
where ref_from like 'Purchase' 
group by format(datee,'mmm-yyyy') 
order by format(datee,'mmm-yyyy') desc 

输出：

Answer 1

尝试按您选择的同一列进行分组：

SELECT t.[Months], t.Amount
FROM
(
    SELECT MONTH(datee) AS theMonth, YEAR(datee) AS theYear,
        FORMAT(datee,'mmm-yyyy') AS [Months], SUM(amount) AS Amount
    FROM ledger_transporter
    WHERE ref_from LIKE 'Purchase'
    GROUP BY MONTH(datee), YEAR(datee), FORMAT(datee, 'mmm-yyyy')
) t
ORDER BY t.theYear DESC, t.theMonth DESC

按日期排序的一种方法是在查询中选择数字月份和年份。

Answer 2

将group by datee更改为group by format(datee,'mmm-yyyy')。

select distinct format(datee,'mmm-yyyy') as [Months], sum(amount) as Amount
from ledger_transporter
where ref_from like 'Purchase'
group by format(datee,'mmm-yyyy')
order by Month(datee)

原因是我假设您的约会时间是01-FEB-2016和02-FEB-2016，但如果按照它分组，您将获得2个不同的记录。 但是，对于format(datee,'mmm-yyyy')，即FEB-2016，这两个日期都相同。因此不匹配