Question

我在查找字符串（topic-link）时遇到了一些麻烦，然后使用awk附加了一个递增的数字。

我有以下html文件，这一行都是一行：

<a class="topic-link" href="test.com/topic/gastrointestinal">Gastrointestinal</a>, <a class="topic-link" href="test.com/topic/nutrition">Nutrition</a>, <a class="topic-link" href="test.com/topic/weight-gain">Weight Gain</a> </p>

使用awk我试图获得：

<a class="topic-link1" href="test.com/topic/gastrointestinal">Gastrointestinal</a>, <a class="topic-link2" href="test.com/topic/nutrition">Nutrition</a>, <a class="topic-link3" href="test.com/topic/weight-gain">Weight Gain</a> </p>

我正在运行以下内容：

awk '{gsub("topic-link","topic-link"++i)}1' input file > output file

问题是结果如下：

<a class="topic-link1" href="test.com/topic/gastrointestinal">Gastrointestinal</a>, <a class="topic-link1" href="test.com/topic/nutrition">Nutrition</a>, <a class="topic-link1" href="test.com/topic/weight-gain">Weight Gain</a> </p>

我提出的解决方案只有在“主题链接”的实例分开的情况下才能正常工作，因此我被卡住了。

请告诉我，我遗漏了一些非常明显的内容，或者您对替代方法有任何建议。

谢谢！

Rylan

Answer 1

你的gsub（）只被调用一次所以我只增加一次。你需要一个循环：

$q = "
            select
            (
            select
                coalesce(
                    (
                        select count(distinct b.username)
                        from recent b
                        where
                            b.istopscore = 1  AND
                            (
                                (
                                    b.score > a.score AND
                                    b.time <= a.time
                                ) OR
                                (
                                    b.score = a.score AND
                                    b.username != a.username AND
                                    b.time < a.time
                                )
                            )
                        ), 0) + 1 Rank
            from scores a
            where a.nickname = ?) as Rank,
            t.time,
            t.username,
            t.score
            from
            scores t
            WHERE t.nickname = ?
            ";

            $r_time = 0;

            if( $stmt = $mysqli->prepare( $q ) )
            {
                $stmt->bind_param( 'ss', $nick, $nick );
                $stmt->execute();
                $stmt->store_result();
                $stmt->bind_result( $r_rank, $r_time, $r_username, $r_score );

                $stmt->fetch();

                if( intval($r_rank) > 99999 )
                    $r_rank = 99999;

                $stmt->close();
            }

            // Previous Rank
            $r_prevrank = -1;

            if( $r_rank > -1 )
            {
                $q = "
                select
                    coalesce(
                        (
                            select count(distinct b.username)
                            from recent b
                            where
                                b.istopscore = 1  AND
                                (
                                    (
                                        b.score > a.score AND
                                        b.time <= a.time
                                    ) OR
                                    (
                                        b.score = a.score AND
                                        b.username != a.username AND
                                        b.time < a.time
                                    )
                                )
                            ), 0) + 1 Rank
                from recent a
                where a.username = ? and a.time < ? and a.score < ?
                order by score desc limit 1";

                if( $stmt = $mysqli->prepare( $q ) )
                {
                    $time_minus_one = ( $r_time - 1 );

                    $stmt->bind_param( 'sii', $r_username, $time_minus_one, $r_score );
                    $stmt->execute();
                    $stmt->store_result();
                    $stmt->bind_result( $r_prevrank );

                    $stmt->fetch();

                    if( intval($r_prevrank) > 99999 )
                        $r_prevrank = 99999;

                    $stmt->close();
                }
                $drop = ($current_rank - $r_rank);
                $drop = ($drop > 0 ? $drop : 0 );


                $increase = $r_prevrank - $r_rank;
                $increase = ($increase > 0 ? $increase : 0 );

                //$change = $increase - $drop;
                $change = ($drop > 0 ? -$drop : $increase);
            }

            return $change;

awk字符串搜索并替换为附加的递增数字

1 个答案: