Question

我刚刚开始创建一个（非常基本的，我刚接触到python）学生数据库，您可以插入学生和详细信息或查看学生及其详细信息。这是迄今为止的代码 -

name = []
age = []
year = []
chosen_subjects =[]
classroom=[]
seat_number=[]
comments=[]
student = [name, age, year, chosen_subjects, classroom, seat_number, comments]


print ("Welcome to Student Database")
print()

while True:
    eorv = input("Press E to enter a new student or V to view existing students ")
    print()
    if eorv == "E" or "e":
        ename = input("Enter student's name")
        name.append(ename)

        eage = input("Enter student's age")`
        age.append(eage)

        eyear = input("Enter student's year")
        year.append(eyear)

        echosen_subjects = input("Enter student's chosen subjects")
        chosen_subjects.append(echosen_subjects)

        eclassroom = input("Enter student's classroom")
        classroom.append(eclassroom)

        eseat_number = input("Enter student's seat number")
        seat_number.append(eseat_number)

        ecomment = input("Enter any comment about this student")
        comments.append(ecomment)

这似乎是问题所在

    elif eorv == "V" or "v":
        print (student)

按下“V”时，它只询问“E”中的所有问题。我不确定为什么会这样，有人可以帮忙吗？

Answer 1

您的问题与if和elif语句一致。这对我有用。

if eorv == "E" or eorv == "e":

你的elif也是如此

if eorv == "V" or eorv == "v:

为什么代码不允许列表打印？

1 个答案: