Question

我正在尝试使用IndexedDB，一切都运行良好，直到几个小时前我的.open（）回调停止在Chrome上调用（在Safari上测试，它工作正常）。

RT.prototype.setupIndexedDB = function (callback) {
  var dbName = "test";
  var dbVersion = 1;
  var indexedDB = window.indexedDB ||
                  window.webkitIndexedDB ||
                  window.mozIndexedDB;

  console.log("setup indexed db");
  var request = indexedDB.open(dbName, dbVersion);
  request.onsuccess = function(e) {
    console.log("db request success");
  };

  request.onblocked = function(e) {
    console.log("DB open blocked", e);
  };

  request.onerror = function(err) {
    console.log("error", err);
  };

  request.onversionchange = function(err) {
    console.log("onversionchange", err);
  };

  request.onupgradeneeded = function(e) {
    console.log("upgrade needed");
  };
};

我查看了Chrome开发人员工具IndexedDB，没有任何内容......

任何人都知道发生了什么事？

谢谢

编辑：完全重新启动浏览器就可以了，但我仍然对了解发生的事情非常感兴趣。

Answer 1

您是否在同一时间尝试删除数据库？如果存在阻塞的挂起deleteDatabase操作，则IndexedDB可能会陷入奇怪的（尽管根据规范是正确的）状态。例如。下面的代码。如果所有其他方法都失败了，您可以检查chrome：// indexeddb-internals，它会告诉您是否有任何待处理的打开或删除操作正在解决问题。

var request = indexedDB.open("test", 1);
request.onblocked = function(e) {
  console.log("DB open blocked", e);
};

request.onerror = function(err) {
  console.log("DB open error", err);
};

request.onupgradeneeded = function(e) {
  console.log("DB open upgrade needed");
};

request.onsuccess = function(e) {
  db = request.result;
  console.log("DB open success");
  db.onversionchange = function(e) {
    console.log("DB got a versionchange event")
  }
  request = indexedDB.deleteDatabase("test");
  request.onsuccess = function(e) {
    console.log("delete success will not be called")
  }
  request.onblocked = function(e) {
    console.log("delete was blocked");
    request = indexedDB.open("test", 1);
    request.onsuccess = function(e) {
      console.log("success won't be called");
    };
    request.onblocked = function(e) {
      console.log("blocked won't be called", e);
    };
    request.onerror = function(err) {
      console.log("error won't be called", err);
    };
    request.onupgradeneeded = function(e) {
      console.log("upgradeneeded won't be called");
    };
  };
};

在Chrome

1 个答案: