在我的网站上,我有一个列表,其中包含可能包含或不包含的不同类别。如果所有这些都是空的,那么整个容器应该被移除,但是如果一个或多个容器里面有内容,则不会发生任何事情。
代码段:
<div class="fts">
<div class="panel-heading">...</div>
<div class="panel-collapse">
<div class="panel-body">
<div class=" bd-layoutbox-16 clearfix">
<div class="bd-container-inner">
<h5>Heading 5</h5>
<div>...</div>
</div>
</div>
<div class=" bd-layoutbox-84 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-31 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-82 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-85 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-86 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-87 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-88 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-89 clearfix">
<div class="bd-container-inner"></div>
</div>
<div class=" bd-layoutbox-90 clearfix">
<div class="bd-container-inner"></div>
</div>
</div>
</div>
</div>
JS
$(".bd-layoutbox-84, .bd-layoutbox-31, .bd-layoutbox-82, .bd-layoutbox-85, .bd-layoutbox-86, .bd-layoutbox-87, .bd-layoutbox-88, .bd-layoutbox-89, .bd-layoutbox-90")
.each(function(){
if($(this).has("h5").length == 0){
$(this).parent().parent().parent().remove();
}
});
问题是什么?
感谢您的帮助。
答案 0 :(得分:0)
你可能需要通过创建一个函数来重新修改你的逻辑,但这是一个想法..
var removethis=1;
$(".bd-layoutbox-84, .bd-layoutbox-31, .bd-layoutbox-82, .bd-layoutbox-85, .bd-layoutbox-86, .bd-layoutbox-87, .bd-layoutbox-88, .bd-layoutbox-89, .bd-layoutbox-90")
.each(function(){
if($(this).has("h5").length > 0){
removethis = 0;
}
});
if (removethis == 1) {
// remove parent item here
}
答案 1 :(得分:0)
您可以使用包含选择器检查是否有任何内容,然后将其删除。以下是代码
$('div.fts').each(function() {
var $this = $(this);
if ($this.find('div[class*="bd-layoutbox-"] h5').length === 0) {
$this.remove();
}
});
演示:arguments