Question

我有以下来自QGIS的xml文件

我想以递归方式替换

中的值“2”

    <?xml version="1.0" encoding="UTF-8"?>
    <kml xmlns="http://www.opengis.net/kml/2.2" xmlns:gx="http://www.google.com/kml/ext/2.2" xmlns:kml="http://www.opengis.net/kml/2.2" xmlns:atom="http://www.w3.org/2005/Atom">
    <Document>
    <name>stationpivot.kml</name>
    <StyleMap id="default0">
        <Pair>
            <key>normal</key>
            <styleUrl>#default</styleUrl>
        </Pair>
        <Pair>
            <key>highlight</key>
            <styleUrl>#hl</styleUrl>
        </Pair>
    </StyleMap>
    <Style id="hl">
        <IconStyle>
            <scale>0.7</scale>
            <Icon>
                <href>http://maps.google.com/mapfiles/kml/shapes/placemark_circle_highlight.png</href>
            </Icon>
        </IconStyle>
        <LabelStyle>
            <scale>0.7</scale>
        </LabelStyle>
    </Style>
    <Style id="default">
        <IconStyle>
            <scale>0.7</scale>
            <Icon>
                <href>http://maps.google.com/mapfiles/kml/shapes/placemark_circle.png</href>
            </Icon>
        </IconStyle>
        <LabelStyle>
            <scale>0.7</scale>
        </LabelStyle>
    </Style>
    <Folder>
        <name>stationXML</name>
        <open>1</open>
        <Placemark>
            <name>2</name>
            <Snippet maxLines="0"></Snippet>
            <description><![CDATA[<html><body><table border="1">
<tr><th>Field Name</th><th>Field Value</th></tr>
<tr><td>Latitude</td><td>26.719803</td></tr>
<tr><td>Longitude</td><td>40.861876</td></tr>
<tr><td>Name</td><td>REALNAME2</td></tr>
<tr><td>Vegetation</td><td>v_type2</td></tr>
<tr><td>Description</td><td>text text text text</td></tr>
<tr><td>Time Description</td><td>time time time </td></tr>
</table></body></html>]]></description>
            <styleUrl>#default0</styleUrl>
            <Point>
                <gx:drawOrder>1</gx:drawOrder>
                <coordinates>40.861876,26.71980299999999,0</coordinates>
            </Point>
        </Placemark>
        <Placemark>
            <name>3</name>
            <Snippet maxLines="0"></Snippet>
            <description><![CDATA[<html><body><table border="1">
<tr><th>Field Name</th><th>Field Value</th></tr>
<tr><td>Latitude</td><td>46.745151</td></tr>
<tr><td>Longitude</td><td>10.788845</td></tr>
<tr><td>Name</td><td>REALNAME3</td></tr>
<tr><td>Vegetation</td><td>v_type3</td></tr>
<tr><td>Description</td><td>text text text text</td></tr>
<tr><td>Time Description</td><td>time time time</td></tr>
</table></body></html>]]></description>
            <styleUrl>#default0</styleUrl>
            <Point>
                <gx:drawOrder>1</gx:drawOrder>
                <coordinates>40.788845,26.74515100000001,0</coordinates>
            </Point>
        </Placemark>

字段使用“描述”字段REALNAME2中包含的信息为了拥有

 <name>2</name>
    <name>3</name>

分别作为我的kml中的最终输出

有什么建议吗？

Answer 1

我建议您将element tree API与XPath一起使用。它非常易于使用且非常强大。它可以让你做你想做的事情：

import xml.etree.ElementTree as ET

root = ET.fromstring(<your KML as string>)
name_list = root.findall(".//Placemark/name")
for name in name_list:
    name.text = "Some new text"

Answer 2

使用pykml模块的完整代码，该模块更新地标名称并创建新的KML文件。

from pykml import parser
import re
import lxml.etree as et

with open('test.kml', 'r') as f:
  doc = parser.parse(f)

for pm in doc.getroot().Document.Folder.Placemark:
  # look for realname in description in markup
  # <tr><td>Name</td><td>*REALNAME2*</td></tr>
  r = re.search(r'<tr><td>Name</td><td>([^<]+)', pm.description.text)
  if r:
    pm.name = r.group(1)

# output new KML file
with open('out.kml', 'wb') as output:
  output.write(et.tostring(doc, pretty_print=True))

使用Pykml解析XML

2 个答案: