Question

我想知道如何让Python检查事件以查看username和password是否匹配，然后打印correct（如果是）或false if它不是。当我尝试时，结果总是false。我需要一种方法来检查它们是否匹配。

这是我的代码：

    from tkinter import *

    root = Tk()

    def check(event):
    username = "Amras"
    password = "pass"
    if entry1 == username:
      if entry2 == password:
        print("true")
    else:
        print("false")
    else:
        print("false")

    name = Label(root, text="Name: ")
    password = Label(root, text="Password: ")
    entry1 = Entry(root)
    entry2 = Entry(root)
    c = Checkbutton(root, text="Keep me logged in")
    button1 = Button(root, text="Login")
    button1.bind("<Button-1>", check)

    name.grid(row=0, sticky=E)
    password.grid(row=1, sticky=E)

    entry1.grid(row=0, column=1)
    entry2.grid(row=1, column=1)

    c.grid(columnspan=2)

    button1.grid(row=1, column=2)

    root.mainloop()

Answer 1

您不会评估放在entry框内的文字。使用entry1.get()等...

from Tkinter import *

root = Tk()

def check(event):
    username = "Amras"
    password = "pass"
    # Also these if statements should be combined
    if entry1.get() == username:   # Use the .get() method
      if entry2.get() == password: # Use the .get() method
        print("true")
    else:
        print("false")


name = Label(root, text="Name: ")
password = Label(root, text="Password: ")
entry1 = Entry(root)
entry2 = Entry(root)
c = Checkbutton(root, text="Keep me logged in")
button1 = Button(root, text="Login")
button1.bind("<Button-1>", check)

name.grid(row=0, sticky=E)
password.grid(row=1, sticky=E)

entry1.grid(row=0, column=1)
entry2.grid(row=1, column=1)

c.grid(columnspan=2)

button1.grid(row=1, column=2)

root.mainloop()

在您输入Amras和pass后，您应该true

同样在你的代码中，import语句似乎很糟糕（Tkinter默认带有大写），定义中有两个else语句，缩进也是错误的。

如何让事件检查条目以查看它是否与Python中的变量匹配

1 个答案: