Question

我需要将数据拉入临时表，以便我可以将其分组为产品类型，但我们目前有某种产品的不同变体，我需要将所有变体作为原始变体插入。我编写的代码如下，但它仍然没有工作

IF EXISTS (SELECT *
           FROM   sys.tables
           WHERE  name LIKE '#temp%')
  DROP TABLE #temp

CREATE TABLE #temp
  (
     Product      VARCHAR(max) NULL,
     failure_code VARCHAR(max) NULL
  )

IF Product IN ( 18, 19, 20, 23,
                24, 25 )
  SELECT Product = 'DSD 4136'

INSERT INTO #temp
            (Product,
             failure_code)
SELECT product.prod_desc AS Product,
       test_failure_code.failure_code
FROM   repair
       INNER JOIN test_failure_code
               ON repair.id_test_failure_code = test_failure_code.id_test_failure_code
       INNER JOIN production_event_details
               ON repair.id_production_event_details = production_event_details.id_production_event_details
       INNER JOIN product
               ON production_event_details.prod_id = product.prod_id
       INNER JOIN repair_scm_bom_item
               ON repair.id_repair = repair_scm_bom_item.id_repair
       INNER JOIN repair_fault
               ON repair_scm_bom_item.id_repair_fault = repair_fault.id_repair_fault
       INNER JOIN scm_bom_item
               ON repair_scm_bom_item.id_scm_bom_item = scm_bom_item.id_scm_bom_item
GROUP  BY product.prod_desc,
          test_failure_code.failure_code

SELECT *
FROM   #temp

DROP TABLE #temp

Answer 1

声明

IF Product IN ( 18, 19, 20, 23, 24, 25 )
SELECT Product = 'DSD 4136'

实际上什么都不做，您需要使用CASE语句在insert语句中使用它，当产品是您列出的选项之一时，这将选择产品DSD 4136：

INSERT INTO #temp
            (Product,
             failure_code)
SELECT CASE WHEN product.prod_desc IN ( 18, 19, 20, 23, 24, 25 ) THEN 'DSD 4136'
  ELSE product.prod_desc
END
AS Product,
       test_failure_code.failure_code
FROM   repair
       INNER JOIN test_failure_code
               ON repair.id_test_failure_code = test_failure_code.id_test_failure_code
       INNER JOIN production_event_details
               ON repair.id_production_event_details = production_event_details.id_production_event_details
       INNER JOIN product
               ON production_event_details.prod_id = product.prod_id
       INNER JOIN repair_scm_bom_item
               ON repair.id_repair = repair_scm_bom_item.id_repair
       INNER JOIN repair_fault
               ON repair_scm_bom_item.id_repair_fault = repair_fault.id_repair_fault
       INNER JOIN scm_bom_item
               ON repair_scm_bom_item.id_scm_bom_item = scm_bom_item.id_scm_bom_item
GROUP  BY product.prod_desc,
          test_failure_code.failure_code

插入具有不同值的数据，然后在临时表中输入

1 个答案: