Question

我有以下代码。当我在网格视图中单击图像时，特定图像应显示在另一个活动中。我怎么能这样做？

这是我的Activity类::

public class ProductsActivity extends Activity {
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.grid_view);

    GridView gridView = (GridView) findViewById(R.id.gridview);
    gridView.setAdapter(new MyAdapter(this));
    gridView.setOnItemClickListener(new AdapterView.OnItemClickListener()
    {
        public void onItemClick(AdapterView<?> parent, View v, int position, long id)
        {
            // this 'mActivity' parameter is Activity object, you can send the current activity.
            Intent i = new Intent(getApplicationContext(), MobileDisplayActivity.class);
            i.putExtra("positionId",position);
            startActivity(i);
        }
    });
}

如何更改我的适配器类以实现我的要求。我想问题出在getView()。

this is my adapter class:
    private class MyAdapter extends BaseAdapter
{
    private List<Item> items = new ArrayList<Item>();
    private LayoutInflater inflater;

    public MyAdapter(Context context)
    {
        inflater = LayoutInflater.from(context);

        items.add(new Item("Image 1", R.drawable.ic_image4));
        items.add(new Item("Image 2", R.drawable.ic_image5));
        items.add(new Item("Image 3", R.drawable.ic_image4));
        items.add(new Item("Image 4", R.drawable.ic_image5));
        items.add(new Item("Image 5", R.drawable.ic_image4));
    }

    @Override
    public int getCount() {
        return items.size();
    }

    @Override
    public Object getItem(int i)
    {
        return items.get(i);
    }

    @Override
    public long getItemId(int i)
    {
        return items.get(i).drawableId;
    }

    @Override
    public View getView(int i, View view, ViewGroup viewGroup)
    {
        View v = view;
        ImageView picture;
        TextView name;

        if(v == null)
        {
            v = inflater.inflate(R.layout.row_grid, viewGroup, false);
            v.setTag(R.id.picture, v.findViewById(R.id.picture));
            v.setTag(R.id.text, v.findViewById(R.id.text));
        }

        picture = (ImageView)v.getTag(R.id.picture);
        name = (TextView)v.getTag(R.id.text);

        Item item = (Item)getItem(i);

        picture.setImageResource(item.drawableId);
        name.setText(item.name);

        return v;
    }

    private class Item
    {
        final String name;
        final int drawableId;

        Item(String name, int drawableId)
        {
            this.name = name;
            this.drawableId = drawableId;
        }
    }
}

}

Answer 1

你应该在意图中输入drawable id，如下面的代码所示：

public void onItemClick(AdapterView<?> parent, View v, int position, long id) {
    int drawableId = ((Item) parent.getItemAtPosition(position)).drawableId;
    Intent intent = new Intent(ProductsActivity.this, MobileDisplayActivity.class);
    intent.putExtra("DRAWABLE_ID", drawableId); 
    startActivity(intent);
}

此外，您应该将Item类设为public static，以便从activity中访问它。 drawableId应该是公共的（或者你可以为这个字段创建一个getter。）

Answer 2

您可以发送ID或您的drawable（也是整数），而不是将项目的位置发送到下一个活动。

这样做

public void onItemClick(AdapterView<?> parent, View v, int position, long id)
{
    // this 'mActivity' parameter is Activity object, you can send the current activity.
    int imageId = ((Item) parent.getItemAtPosition(position)).drawableId;
    Intent i = new Intent(getApplicationContext(), MobileDisplayActivity.class);
    i.putExtra("imageId", imageId);
    startActivity(i);
 }

在MobileDisplayActivity活动中，简单地执行此操作

int imageId = getIntent().getIntExtra("imageId", 0);
if(imageId > 0)
    imageView.setBackgroundResource(imageId);
else
    // something went wrong

注意：将Item类设为public static或单独定义。

如何显示以下代码的基于位置的图像？

2 个答案: