如果某行包含搜索到的值,我想删除搜索到的值(不是行)。例如,如果我想删除banana,它应该只从包含banana的行中删除banana。
试过这个,
DELETE FROM users where eat like '%banana%'
但是,它删除了行。那么如何才能从行中删除搜索值呢?
答案 0 :(得分:2)
UPDATE users SET eat = null where eat like '%banana%';
OR
UPDATE users SET eat = '' where eat like '%banana%';
答案 1 :(得分:2)
你可以试试这个 -
UPDATE users SET eat = REPLACE(eat, 'banana', '') where eat like '%banana%';
这只会替换banana
列中存在的eat
。
<强>更新强>
循环遍历数据并替换这些值。这可能会有所帮助 -
$check_val = 'banana';
//select those rows first
"select id, eat from users where eat like '%" . $check_val . "%'"
foreach($data as $v) {
$temp= explode(',', $v['eat']);
$temp= array_map(function($t) use($check_val) {
return (strpos($t, $check_val) !== false) ? null : $t;
}, $temp);
$temp = array_filter($temp);
$v['eat']= implode(',', $temp);
"update users set eat= '" . $v['eat'] . "' where eat like '%" . $check_val . "%'"
}
答案 2 :(得分:1)
尝试此查询:
update users set eat='' where eat like '%banana%'
答案 3 :(得分:1)
Update users
set eat = 'your value'
where eat like '%banana%' ;