Question

我使用以下代码来读取指定的XML

<?xml version=\"1.0\" encoding=\"UTF-8\"?>
<feed version=\"0.3\" xmlns=\"http://purl.org/atom/ns#\">
    <title>Gmail - Inbox for xxxx@gmail.com</title>
    <tagline>New messages in your Gmail Inbox</tagline>
    <fullcount>1</fullcount>
    <link rel=\"alternate\" href=\"https://mail.google.com/mail\" type=\"text/html\" />
    <modified>2016-02-07T12:11:21Z</modified>
    <entry>
        <title>Access for less secure apps has been turned on</title>
        <summary>Access for less secure apps has been turned on Hi Buddy, You recently changed your security settings so</summary>
        <link rel=\"alternate\" href=\"https://mail.google.com/mail?account_id=agl.testauto@gmail.com&amp;message_id=152bb8ccd28d824b&amp;view=conv&amp;extsrc=atom\" type=\"text/html\" />
        <modified>2016-02-07T11:45:12Z</modified>
        <issued>2016-02-07T11:45:12Z</issued>
        <id>tag:gmail.google.com,2004:1525516088640373323</id>
        <author>
            <name>Google</name>
            <email>no-reply@accounts.google.com</email>
        </author>
    </entry>
</feed>

正在使用下面的代码，问题是我没有获得最后一行代码的title元素的值。

response = Encoding.UTF8.GetString(objclient.DownloadData("https://mail.google.com/mail/feed/atom"));
response = response.Replace("<feed version*\"0.3\" xmlns=\"http://purl.org/atom/01#\">", "<feed>");

xdoc.LoadXml(response);

var nsmgr = new XmlNamespaceManager(xdoc.NameTable);
nsmgr.AddNamespace("feed", "http://purl.org/atom/ns#");
node = xdoc.SelectSingleNode("//feed:fullcount", nsmgr);


Variables.emailcount = Convert.ToInt16(node.InnerText);
System.Diagnostics.Debug.Write(Variables.emailcount);

tagline = xdoc.SelectSingleNode("//feed:tagline", nsmgr).InnerText;

node2 = xdoc.SelectSingleNode("//feed:entry", nsmgr);

message_subject = node2.SelectSingleNode("//feed/entry/title", nsmg).InnerText;    ---- >>>  Issue Line

只是想知道问题出在哪里。

由于

Answer 1

使用来自SyndicationFeed程序集的System.ServiceModel.Syndication命名空间中的System.ServiceModel，让您的生活更轻松。

SyndicationFeed syndicationFeed = null;
using (var reader = XmlReader.Create("https://mail.google.com/mail/feed/atom"))
{
    syndicationFeed = SyndicationFeed.Load(reader);
}

if(syndicationFeed != null)
{
    foreach (SyndicationItem item in syndicationFeed.Items)
    {
        // Do everything you want here by checking properties you need from SyndicationItem item variable.
    }
}

要了解SyndicationItem提供的属性，请查看此link。

Answer 2

试

message_subject = node2.SelectSingleNode（“// feed：entry / feed：title”， nsmgr）.InnerText;

注意：您已使用“feed”作为命名空间的名称，因此标题也应该是合格的

Answer 3

我更喜欢xml linq

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const int NUMBER_OF_XML = 3;
        static void Main(string[] args)
        {
            string xml =
                "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" +
                    "<feed version=\"0.3\" xmlns=\"http://purl.org/atom/ns#\">" +
                        "<title>Gmail - Inbox for xxxx@gmail.com</title>" +
                        "<tagline>New messages in your Gmail Inbox</tagline>" +
                        "<fullcount>1</fullcount>" +
                        "<link rel=\"alternate\" href=\"https://mail.google.com/mail\" type=\"text/html\" />" +
                        "<modified>2016-02-07T12:11:21Z</modified>" +
                        "<entry>" +
                            "<title>Access for less secure apps has been turned on</title>" +
                            "<summary>Access for less secure apps has been turned on Hi Buddy, You recently changed your security settings so</summary>" +
                            "<link rel=\"alternate\" href=\"https://mail.google.com/mail?account_id=agl.testauto@gmail.com&amp;message_id=152bb8ccd28d824b&amp;view=conv&amp;extsrc=atom\" type=\"text/html\" />" +
                            "<modified>2016-02-07T11:45:12Z</modified>" +
                            "<issued>2016-02-07T11:45:12Z</issued>" +
                            "<id>tag:gmail.google.com,2004:1525516088640373323</id>" +
                            "<author>" +
                                "<name>Google</name>" +
                                "<email>no-reply@accounts.google.com</email>" +
                            "</author>" +
                        "</entry>" +
                    "</feed>";

            XDocument doc = XDocument.Parse(xml);
            XElement firstNode = (XElement)doc.FirstNode;
            XNamespace ns = firstNode.Name.Namespace;
            var results = doc.Elements(ns + "feed").Select(x => new {
                    tagline = (string)x.Element(ns + "tagline"),
                    message_subject = (string)x.Element(ns + "entry").Element(ns + "title")
                }).FirstOrDefault();


        }
    }
}

使用SelectSingleNode读取XML

3 个答案: