Question

您好，我试图选择movementline.qty的值，但仅当movements.movementscode等于RW时，如果不是仅仅为0.00

SELECT levelfield1.description,
       products.reportuom,
       products.productcode,
       products.description,
       Isnull(Sum(ReceivingLine.qty), 0.00)       AS [B.Delivery],
       movements.movementcode,
       Isnull((SELECT qty
               FROM   MovementLine
               WHERE  movementcode = 'RW'), 0.00) AS [B. Returned]
FROM   Products
       LEFT JOIN LevelField1
              ON levelfield1.levelfield1code = products.levelfield1code
       LEFT JOIN ReceivingLine
              ON receivingline.PRODUCTCODE = products.productcode
       LEFT JOIN MovementLine
              ON movementline.ProductCode = products.productcode
       LEFT JOIN Movements
              ON movements.MovementID = MovementLine.movementid
GROUP  BY levelfield1.Description,
          products.reportuom,
          products.productcode,
          products.description,
          movementline.qty,
          movements.movementcode

我收到了错误

子查询返回的值超过1。这是不允许的子查询跟随=，！=，＆lt;，＆lt; =，＆gt;，＆gt; =或当子查询用作一种表达。警告：聚合或消除空值其他SET操作。

Answer 1

您的代码需要深入思考。因为可能存在加入问题而您可能无法获得正确的结果。问题将使用前1解决，但无法获得正确的结果。所以这里需要使用CASE。我希望您的问题能够通过使用波纹管代码解决。

select levelfield1.description, products.reportuom, products.productcode,
        products.description ,ISNULL(SUM(ReceivingLine.qty),0.00) as [B.Delivery], 
  movements.movementcode,
  CASE 
    WHEN movementline.movementcode = 'RW' THEN ISNULL(movementline.qty,0.00)
    ESLE 0.00
  END AS [Returned]

  from Products 
  left join LevelField1 on levelfield1.levelfield1code = products.levelfield1code
  left join ReceivingLine on receivingline.PRODUCTCODE = products.productcode
  left join MovementLine on movementline.ProductCode = products.productcode
  left join Movements on movements.MovementID = MovementLine.movementid 
  group by levelfield1.Description, products.reportuom, products.productcode, products.description, movementline.qty,movements.movementcode

子查询返回的值超过1。 VB6

1 个答案: