python编程时发生Elif错误

时间:2016-02-08 01:53:10

标签: python

# Get the input values.
b1 = input('Please enter the base.')
i1 = input('Please enter the index.')

# Define the funciton with parameter 'base' and 'index'.
def square(base, index):
    if base == 0:
        print('Can\'t calculate because base is equal to 0.')
    elif (not base == 0) and index == 0:
        print('The value is 0, because base is greater than 1, and index is equal to 0.')
    elif (not base == 0) and index == 1:
        print('The answer is equal to base, because index is equal to 1. Therefore, The answer is {ans}.'.format(ans=base))
    elif (not base == 0) and index == 2:
        print('{b} squared is {c}.'.format(b=base, c=(b ** 2))
    elif (not base == 0) and (index > 2 or index < 0):
        print('{b} to the power of {i} is equal to {c}'.format(b=base, i=index, c=base**index))

# Print the function.
print(square(b1, i1))

错误是这样的:

第36行,elif(不是base == 0)和(index&gt; 2或index&lt; 0):

SyntaxError:语法无效

我使用python 3.5.1。 我该如何解决这个错误?

1 个答案:

答案 0 :(得分:1)

问题不在于该行,而是在上面的行上。你没有关闭足够的括号。尝试在上一行的末尾添加另一个右括号。