我知道这是一个已知问题,但我在解决问题上遇到了困难。当我通过FileUploader将图像发送到我的服务器时,我的UI5应用程序似乎没有收到任何内容。我是HCP的新手,这是我第一次处理XSJS文件。我希望你能帮助我。
sap.ui.define([
"sap/ui/core/mvc/Controller"
], function(Controller) {
"use strict";
return Controller.extend("sample.controller.View1", {
handleUploadPress : function(oEvent)
{
var fileLoader =this.getView().byId("FileLoader");//XML View
var fileName = fileLoader.getValue();
jQuery.sap.require("sap.ui.commons.MessageBox");
if (fileName === "" )
{
sap.ui.commons.MessageBox.show("Please choose File.", sap.ui.commons.MessageBox.Icon.INFORMATION, "Information");
}
else
{
var uploadUrl = "https://xxxxxx/services/Sample.xsjs?file_name="+fileName;
var formEle = jQuery.sap.domById("UpdateContact--FileLoader");
var form = $(formEle).find("form")[0] ;
var fd = new FormData(form);
$.ajax({
url: uploadUrl,
type: "GET",
beforeSend: function(xhr)
{
xhr.setRequestHeader("X-CSRF-Token", "Fetch");
},
success: function(data, textStatus, XMLHttpRequest) {
var token = XMLHttpRequest.getResponseHeader('X-CSRF-Token');
$.ajax({
url: uploadUrl,
type: "POST",
processData :false ,
contentType: false,
data: fd,
beforeSend: function(xhr)
{
xhr.setRequestHeader("X-CSRF-Token", token);
},
success: function(data, textStatus, XMLHttpRequest)
{
var resptext = XMLHttpRequest.responseText;
jQuery.sap.require("sap.ui.commons.MessageBox");
sap.ui.commons.MessageBox.show(resptext, sap.ui.commons.MessageBox.Icon.INFORMATION, "Information");
if(data === "Upload successful"){
sap.ui.commons.MessageBox.show("File uploaded.", sap.ui.commons.MessageBox.Icon.INFORMATION, "Information");
}
},
error: function(data, textStatus, XMLHttpRequest)
{
sap.ui.commons.MessageBox.show("File could not be uploaded.", sap.ui.commons.MessageBox.Icon.ERROR, "Error");
}
});
}} ) ;
}
}
});
XSJS服务:
$.response.contentType = "text/html";
try
{
var conn = $.hdb.getConnection();
var filename = $.request.parameters.get("file_name");
var headers = $.entity.headers.length;
var pstmt = conn.prepareStatement("INSERT INTO \"XXX_ASSETS\".\"XXX\" VALUES('1',?,'test',CURRENT_USER,CURRENT_TIMESTAMP)");
if($.request.entities.length > 0){
var file_body = $.request.entities[0].body.asArrayBuffer();
pstmt.setBlob(1,file_body);
pstmt.execute();
$.response.setBody("[200]:Upload successful!");
}
else
{
$.response.setBody("No Entries");
}
pstmt.close();
conn.commit();
conn.close();
}
catch(err)
{
if (pstmt !== null)
{
pstmt.close();
}
if (conn !== null)
{
conn.close();
}
$.response.setBody(err.message);
}
}
我的代码是基于我在互联网上找到的教程构建的。谢谢。
答案 0 :(得分:0)
保存图像的一种好方法是转换(Base64)并将其另存为HANA表中的blob。
致谢