Question

我有一个来自Model / registro.php的查询，它向我返回一个值Controllers / registro.php，我必须将数据返回给ajax，但不是。什么可能是Controllers / registro.php的问题没有返回任何成功的东西：function（data）ajax

型号/ registro.php

public function registrar($username,$email,$password,$confirm_password)
{




     try{

                $this->has= crypt($password);
                $this->has_con= crypt($confirm_password);
                $p= true;

                $registro=$this->conexion->conexion->query("insert into registro_por (nombre, correo, pass, conf_pass) values( '$username','$email','$this->has','$this->has_con')");


                 if($registro)
                 {
                         return $p;

                 }else{

                    throw new Exception("Fallos la ejecución");

                 }



     }catch(Exception $e){

             echo 'Message: '.$e->getMessage();

     }






 }

控制器/ registro.php

require_once("../Model/registro.php");

  $username =$_POST["username"];
  $email =$_POST["email"];
  $password =$_POST["password"];
  $confirm_password =$_POST["confirm_password"];


 $reg = new Registro();

 $t=$reg->registrar($username,$email,$password,$confirm_password);  
  $respuesta="soy controllers";
  $fail="segenero un erro";
 //var_dump($t);
 //echo ($t); 
if($t == true){
    //return "ok";
    header('Content-Type: application/json');
    echo json_encode($respuesta);

}else{
    header('Content-Type: application/json');
    echo json_encode($fail);
    //echo "fail";
    //echo json_encode("fail");
 }

Ajax jquery

$('#register-submit').click(function(){


  var data= $('#register-form').serialize();

    $.ajax({
             beforeSend:function(){
                console.log(data);
             },
             type:'POST',
             url:'../Controllers/registro.php',
             data:data,
             dataType:"json",
             success: function(data){
                   console.log('nanananana');
                   console.log("soy data"+data);
             }

       });

 });

Answer 1

尝试使用xfa.host.print(1, "0", (xfa.host.numPages -1).toString(), 0, 0, 0, 0, 0);

停止提交事件

e.preventDefault();

这里提到了相同的案例

jquery ajax jqXHR.status is always 0

控制器不会将数据返回给ajax

1 个答案: