Question

销售数据包含可以转换任何字符的动态产品名称。

动态数据透视表是根据来自的示例创建的 Crosstab with a large or undefined number of categories

translate（）用于删除不良字符。

在结果数据透视表中，列名已损坏：删除了缺少的字符和空格。如何返回与源数据中的列名相同的数据？我试着用

  quote_ident(productname) as tootjakood,

而不是

  'C'||upper(Translate(productname,'Ø. &/+-,%','O')) as tootjakood,

但它返回错误

错误：列“Ø，12.3 / 3mm”不存在

测试用例：

create temp table sales ( saledate date, productname char(20), quantity int );
insert into sales values ( '2016-1-1', 'Ø 12.3/3mm', 2);
insert into sales values ( '2016-1-1', '+-3,4%/3mm', 52);
insert into sales values ( '2016-1-3', '/3,2m-', 246);

do $do$


declare
voter_list text;
begin

create temp table myyk on commit drop as
select saledate as kuupaev,
  'C'||upper(Translate(productname,'Ø. &/+-,%','O')) as tootjakood, 
  sum(quantity)::int as kogus 
from sales
group by 1,2
;

drop table if exists pivot;

voter_list := (
    select string_agg(distinct tootjakood, ' ' order by tootjakood) from myyk
    );

execute(format('
    create table pivot (
kuupaev date,
        %1$s
    )', (replace(voter_list, ' ', ' integer, ') || ' integer')
));

execute (format($f$

  insert into pivot
        select
           kuupaev,
            %2$s
        from crosstab($ct$
            select
                kuupaev,tootjakood,kogus
            from myyk
            order by 1
            $ct$,$ct$
            select distinct tootjakood
            from myyk
            order by 1
            $ct$
        ) as (
            kuupaev date,
            %4$s
        );$f$,

        replace(voter_list, ' ', ' + '),
        replace(voter_list, ' ', ', '),
        '',
        replace(voter_list, ' ', ' integer, ') || ' integer'  -- 4.
    ));
end; $do$;

select * from pivot;

使用Postgres 9.1。

Answer 1

你应该使用双引号。因为您使用空格来标识列分隔符，所以应该从列名中删除空格（或更改分隔符标识的方式）。

使用

//...
while ((line = br.readLine()) != null) {
    String[] values = line.split("\t");
    //To ensure it's still valid data
    if (values.length >= 1 && values.length <= 2) {
        String addedTask = values[0];
        String enteredDueDate;
        //Check whether dueDate has a value or is empty
        if (values.length == 1)
            enteredDueDate = "";
        else
            enteredDueDate = values[1];
        DueDate d = new DueDate(addedTask, enteredDueDate);
        tasks.add(d);
    }
}
//...

你会得到：

//...
while ((line = br.readLine()) != null) {
    String[] values = line.split("\t");
    if (values.length >= 1 && values.length <= 2)
        tasks.add(new DueDate(values[0], values.length == 1 ? "" : values[1]));
}
//...

如何在动态数据透视表

1 个答案: