使用PHP上传文件

时间:2016-02-07 12:37:24

标签: php file

我想将文件上传到指定的文件夹。

<?php
$folder = "upload/";
if (is_uploaded_file($HTTP_POST_FILES['filename']['tmp_name']))  {   
    if (move_uploaded_file($HTTP_POST_FILES['filename']['tmp_name'], $folder.$HTTP_POST_FILES['filename']['name'])) {
         echo "File uploaded";
    } else {
         echo "File not moved to destination folder. Check permissions";
    };
} else {s
     echo "File is not uploaded";
}; 
?>

错误是:

  

注意:未定义的变量:第3行的C:\ wamp \ www \ sdg \ import \ ips.php中的HTTP_POST_FILES

7 个答案:

答案 0 :(得分:5)

以下是上传文件的一种方法,还有很多方法。

正如@nordenheim所说,自PHP 4.1.0以来,$HTTP_POST_FILES已被弃用,因此不建议使用它。

PHP代码(upload.php)

<?php
$target_dir = "upload/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file, PATHINFO_EXTENSION);

// Check if image file is a actual image or fake image
if (isset($_POST["submit"])) {

    if ($target_file == "upload/") {
        $msg = "cannot be empty";
        $uploadOk = 0;
    } // Check if file already exists
    else if (file_exists($target_file)) {
        $msg = "Sorry, file already exists.";
        $uploadOk = 0;
    } // Check file size
    else if ($_FILES["fileToUpload"]["size"] > 5000000) {
        $msg = "Sorry, your file is too large.";
        $uploadOk = 0;
    } // Check if $uploadOk is set to 0 by an error
    else if ($uploadOk == 0) {
        $msg = "Sorry, your file was not uploaded.";

        // if everything is ok, try to upload file
    } else {
        if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
            $msg = "The file " . basename($_FILES["fileToUpload"]["name"]) . " has been uploaded.";
        }
    }
}

?>

启动功能的HTML代码

<form action="upload.php" method="post" id="myForm" enctype="multipart/form-data">
    Select file to upload:
    <input type="file" name="fileToUpload" id="fileToUpload">
    <button name="submit" class="btn btn-primary" type="submit" value="submit">Upload File</button>
 </form>

希望这有帮助。

答案 1 :(得分:3)

PHP 4.1引入了superglobals。它们替换了包含从请求中提取的数据的旧的,长命名的数组。已将$_FILES[]替换为$HTTP_POST_FILES[],将$_GET[]替换为$HTTP_GET_VARS[],依此类推

对于后续的PHP 4版本,旧的和新的阵列可以并排使用。默认情况下,PHP 5禁用了旧数组的生成,并引入了可用于重新启用旧数组创建的php.ini directive register_long_arrays

自PHP 5.4起,旧的长名称数组被完全删除,register_long_arrays与它们一起被移除。

结论:您正在从一个非常古老或非常糟糕的教程中学习。找一个更好的。

答案 2 :(得分:0)

 public static function uploadFile($filepath="upload",$existCheck=0,$uniq=0){
   global $_FILES;
   try {
        // Undefined | Multiple Files | $_FILES Corruption Attack
        // If this request falls under any of them, treat it invalid.
        if (
            !isset($_FILES['uploaded_file']['error']) ||
            is_array($_FILES['uploaded_file']['error'])
        ) {
            $result["status"]="fail";$result["errors"]=('Invalid parameters.');return $result;
        }


        // Check $_FILES['uploaded_file']['error'] value.
        switch ($_FILES['uploaded_file']['error']) {
            case UPLOAD_ERR_OK:
                break;
            case UPLOAD_ERR_NO_FILE:
                $result["status"]="fail";$result["errors"]=('No file sent.');return $result;
            case UPLOAD_ERR_INI_SIZE:
            case UPLOAD_ERR_FORM_SIZE:
                $result["status"]="fail";$result["errors"]=('Exceeded filesize limit.');return $result;
            default:
                $result["status"]="fail";$result["errors"]=('Unknown errors.');return $result;
        }

        // You should also check filesize here. 
        if ($_FILES['uploaded_file']['size'] > 1000000) {
            $result["status"]="fail";$result["errors"]=('Exceeded filesize limit.');return $result;
        }

        // DO NOT TRUST $_FILES['uploaded_file']['mime'] VALUE !!
        // Check MIME Type by yourself.
        $finfo = new finfo(FILEINFO_MIME_TYPE);
        if (false === $ext = array_search(
            $finfo->file($_FILES['uploaded_file']['tmp_name']),
            array(
                'jpg' => 'image/jpeg',
                'png' => 'image/png',
                'gif' => 'image/gif',
            ),
            true
        )) {
            $result["status"]="fail";$result["errors"]=('Invalid file format.');return $result;
        }
        if($uniq==0){
            $temp=$filepath;
        }
        else{
            $temp=$filepath."/".uniqid()."_".$_FILES['uploaded_file']['name'];
        }

        if ($existCheck==1 && file_exists($temp)) {
            $result["status"]="fail";$result["errors"]=('Unknown errors.');return $result;
        }
        if(@copy($_FILES['uploaded_file']['tmp_name'], $temp)) {
            return $result["status"]="success";
        } 
        $result["status"]="fail";$result["errors"]=('Unknown errors.');return $result;

    } catch (Exception $e) {

            $result["status"]="fail";$result["errors"]= $e->getMessage();return $result;

    }
}

答案 3 :(得分:0)

首先,编写这样的html代码,不要忘记添加enctype="multipart/form-data"

<form action="upload.php" method="post" enctype="multipart/form-data">
  <input type="file" name="fileToUpload" id="fileToUpload">
  <input type="submit" value="Upload Image" name="submit">
</form>

然后创建一个名为upload.php的文件名

<?php
$path = "form/";
$target_file =  $path.basename($_FILES["fileToUpload"]["name"]);
$file=$_FILES['fileToUpload']['name'];    
$result = move_uploaded_file($_FILES['fileToUpload']['tmp_name'],$target_file.$file);
if ($result) {
    echo "file successfully uploaded";
}
else {
    echo "please select your file";
}

答案 4 :(得分:0)

您应该尝试

    $fileType = $_FILES['profileimage']['type'];
    $fileName = $_FILES['profileimage']['name'];

    $array = explode(".", $fileName);
    $ext  = $array[count($array)-1];

     $imageAutoName = "profileimagehr".$rsinssupp.".".$ext;


    if(!move_uploaded_file($_FILES['profileimage']['tmp_name'],'img/user/'.$imageAutoName))     
    {
      $msg = "";
    }
    else
    {
      $iquery = "UPDATE tblname SET  filane = '".$imageAutoName."' WHERE id = ".$rsinssupp."";
      $obj->edit($iquery);
    }

答案 5 :(得分:0)

index.php

<?php
   if(isset($_FILES['image'])){
      $errors= array();
      $file_name = $_FILES['image']['name'];
      $file_tmp =$_FILES['image']['tmp_name'];
      $extensions= array("jpeg","jpg","png");
      move_uploaded_file($file_tmp,"images/".$file_name);     
   }
?>
<html>
   <body>

      <form action="" method="POST" enctype="multipart/form-data">
         <input type="file" name="image" />
         <input type="submit"/>
      </form>

   </body>
</html>

在项目文件夹中创建一个图像文件夹,然后运行此文件。

答案 6 :(得分:0)

您好,您可以使用phpUpload

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