Question

我一直在快速开发应用程序几个月，而且我无法弄清楚如何将数据传递到图表。基本上我所拥有的是一个内部有数组的视图控制器，以及一个包含图表的UIView。我想要做的是UIView中的图形在ViewController中绘制数组。所以我想要的是视图控制器中数组dataMoneyTracker1的数据传递给UIView中的数组graphPoints，或者我可以从uiview访问视图控制器中的数组。

感谢您的回答！

这是我的代码：

查看控制器

import UIKit

class GonDetail2ViewController: UIViewController {
var dataMoneyTracker1 = [Int]()
@IBOutlet var View1: UIView!

}

的UIView

import UIKit

class GonGraphUIView: UIView {


    var graphPoints = [Int]()

    override func drawRect(rect: CGRect) {
        let width = rect.width
        let height = rect.height

        let margin:CGFloat = 20.0
        let columnXPoint = { (column:Int) -> CGFloat in
            //Calculate gap between points
            let spacer = (width - margin*2 - 4) /
                CGFloat((self.graphPoints.count - 1))
            var x:CGFloat = CGFloat(column) * spacer
            x += margin + 2
            return x



    }

        let topBorder:CGFloat = 60
        let bottomBorder:CGFloat = 50
        let graphHeight = height - topBorder - bottomBorder
        let maxValue = graphPoints.maxElement()
        let columnYPoint = { (graphPoint:Int) -> CGFloat in
            var y:CGFloat = CGFloat(graphPoint) /
                CGFloat(maxValue!) * graphHeight
            y = graphHeight + topBorder - y // Flip the graph
            return y
        }

        UIColor.whiteColor().setFill()
        UIColor.whiteColor().setStroke()

        //set up the points line
        let graphPath = UIBezierPath()
        //go to start of line
        graphPath.moveToPoint(CGPoint(x:columnXPoint(0),
            y:columnYPoint(graphPoints[0])))

        //add points for each item in the graphPoints array
        //at the correct (x, y) for the point
        for i in 1..<graphPoints.count {
            let nextPoint = CGPoint(x:columnXPoint(i),
                y:columnYPoint(graphPoints[i]))
            graphPath.addLineToPoint(nextPoint)
        }

        graphPath.stroke()

        graphPath.lineWidth = 2.0
        graphPath.stroke()

        //Draw the circles on top of graph stroke
        for i in 0..<graphPoints.count {
            var point = CGPoint(x:columnXPoint(i), y:columnYPoint(graphPoints[i]))
            point.x -= 5.0/2
            point.y -= 5.0/2

            let circle = UIBezierPath(ovalInRect:
                CGRect(origin: point,
                    size: CGSize(width: 5.0, height: 5.0)))
            circle.fill()
        }

    /*
    // Only override drawRect: if you perform custom drawing.
    // An empty implementation adversely affects performance during animation.
    override func drawRect(rect: CGRect) {
        // Drawing code
    }
    */

}
}

Answer 1

可以使用此变量重新定义UIViewController：

@IBOutlet var View1: GonGraphUIView!

并在GonGraphUIView

var graphPoints:[Int]?

然后在drawRect

if let graphPoints = graphPoints {
    // draw the graph
} else { do nothing }

所以UIViewController可以说

View1.graphPoints = dataMoneyTracker1
View1.setneedsDisplay()

Answer 2

有两种方法可以解决这个问题。

最简单的方法是在任何类之外定义var dataMoneyTracker1 = [Int]()，然后您可以随时访问它。或者您可以将其设为类变量，然后您可以访问它：

class GonDetailViewController: UIViewController{
    static var dataMoneyTracker1 = [Int]()
}
class GonGraphUIView : UIView{
    var graphPoints = GonDetailViewController.dataMoneyTracker1
}

swift中

2 个答案: