Question

你能帮我写一个困难的查询来计算wordpress上的点数吗？

情况如下：

在wordpress网站上有一个广告系统并搜索（过滤）。
主页会显示所有类别的列表，其中包含每个类别中的广告数量。
用户以城市，广告类型和关键字的形式输入。他可以输入所有参数或仅输入其中一个参数。
脚本应显示每个类别中的广告数量。

我的脚本有效，但速度非常慢。

<?php

 $querystr = "SELECT *  FROM $wpdb->posts
INNER JOIN wp_term_relationships ON (wp_posts.ID = wp_term_relationships.object_id)
INNER JOIN wp_term_taxonomy ON (wp_term_relationships.term_taxonomy_id = wp_term_taxonomy.term_taxonomy_id)
WHERE (wp_term_taxonomy.term_id = ".$category->cat_ID." AND wp_term_taxonomy.taxonomy = 'category'
AND wp_posts.post_type = 'post'
AND wp_posts.post_status = 'publish')";

$pageposts = $wpdb->get_results($querystr, OBJECT);

$count=0;
foreach($pageposts as $post) { 
setup_postdata($post); 

$today = date('Y-m-d H:i:S');

$validity = get_post_meta($post->ID, 'valid_until', true);

$city = get_post_meta($post->ID, 'post_location', true);

$action = get_post_meta($post->ID, 'post_action', true);


$cities = explode("|", $city);

$session_city = $_SESSION["session_city"];

if($_SESSION["session_city"] and !$_SESSION["session_action"] or $_SESSION["session_action"]=='All') {
    if($validity >= $today and in_array($session_city, $cities)) { $count++;}
}

if($_SESSION["session_action"] and !$_SESSION["session_city"] or $_SESSION["session_city"]=='All') {
    if($validity >= $today and $action == $_SESSION["session_action"]) { $count++;}
}

if($_SESSION["session_action"] and $_SESSION["session_city"]) {
    if($validity >= $today and $action == $_SESSION["session_action"] and in_array($session_city, $cities)) { $count++;}
}

if(!isset($_SESSION["session_city"]) and !isset($_SESSION["session_action"])) {
    if($validity >= $today) { $count++;}
}


}

echo $count;

?>

Answer 1

wp_term_taxonomy needs INDEX(taxonomy, term_id)
wp_term_relationships needs INDEX(term_taxonomy_id, object_id)

请提供SHOW CREATE TABLE wp_term_relationships;我怀疑它没有最佳定义。（我假设它是另外两个表之间的多对多关系？）

如果可能，请提供EXPLAIN SELECT ...。

Cookbook on building indexes

困难的mysql查询wordpress

1 个答案: