我可以输入下面一段代码中提到的多个学生详细信息,方法是单击每行旁边的+符号,如果不需要,则删除bin符号:
<tr class="firstclass" id="school0">
<td ><input type="text" id="rollnum" name="rollnum" class="rollClass" maxlength="20"/></td>
<td ><select id="school" name="school" multiple="multiple" style="width: 95px; size: 50px" size="3" class="schoolClass"></td>
<td><img src="<c:url value="/images/add_small.png"/>" id="btnAdd1" class="addImg"/></td>
<td><img src="images/delete_small.png" id="btnDelete1" class="delImg"/></td >
</tr>
<tr class="secondclass" id="college0">
<td ><input type="text" id="rollnum" name="rollnum" class="rollClass" maxlength="20"/></td>
<td ><select id="college" name="college" multiple="multiple" style="width: 95px; size: 50px" size="3" class="schoolClass"></td>
<td><img src="<c:url value="/images/add_small.png"/>" id="btnAdd1" class="addImg"/></td>
<td><img src="images/delete_small.png" id="btnDelete1" class="delImg"/></td >
</tr>
但是,如果我作为json字符串收到了超过1行的数据,那么如何展示它们是棘手的。
$.ajax({
dataType: "json",
type: "POST",
url: 'get_StudentList',
async: false,
data: {
schrollnum: schrollnum,
school: school,
colrollnum: collrollnum,
college: college
},
success: function(response) {
// No clue if I had received around 10 rows of data
}
一切都在jquery
答案 0 :(得分:0)
您可以执行类似此示例的操作,我建议您在chrome中成功调用内添加断点以检查响应数据,或者您可以在编写任何代码之前使用网络选项卡查看响应。代码取决于响应JSON结构,因此请检查chrome developer工具中的网络选项卡以查看响应JSON结构。
$.ajax({
dataType : "json",
type : "POST",
url : 'get_StudentList',
async : false,
data : {
schrollnum: schrollnum,
school: school,
colrollnum: collrollnum,
college: college
},
success : function(response) {
//Open your website in chrome and a breakpoint at this line and then you can play with the response data in developer console
//If your response is in JSON format then you can directly check it like
if(response.students && response.students.length){
//Insert elements to DOM from data received
}
//If your response is in String format then you will need to parse it
var studentData = JSON.parse(response);
if(studentData.students && studentData.students.length){
//Insert elements to DOM from data received
}
}
});
答案 1 :(得分:0)
您可以迭代您的回复并将行追加到表中:
success : function(response) {
var htmlTemplate = '', schoolId;
response.aaData.forEach( function(item){
if ( item.schrollnum ){
schoolId = item.schrollnum;
} else {
schoolId = item.colrollnum;
}
htmlTemplate += '<tr class="firstclass" id="' + schoolId + '"><td>...</td></tr>';
});
$('#table').append(htmlTemplate);
}