通过java

时间:2016-02-07 01:14:17

标签: java web-scraping httprequest

我试图从一个名为alphadraft.com的网站中搜索一些数据。不幸的是,我需要对自己进行身份验证以访问该数据。经过一段时间的搜索后,我了解到我需要向登录我的网站发送一个POST请求。通过Chrome DevTools,我了解到this应该是应该登录我的帖子请求。< / p>

在搜索了如何做到这一点之后,我偶然发现了这个答案并决定复制以达到我的目的。 How to send Request payload to REST API in java?

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import java.net.HttpURLConnection;
import java.io.OutputStreamWriter;


public class testasdf {

    public static void main(String[] args) throws IOException, NumberFormatException {

          String line;
            StringBuffer jsonString = new StringBuffer();
            try {

                URL url = new URL("https://alphadraft.com/api/ui/auth/loginuser/");

                //escape the double quotes in json string
                String payload="{email_address : \"(EMAILHERE)\", password : \"(PASSWORDHERE)\"}";
                System.out.println(payload);

                HttpURLConnection connection = (HttpURLConnection) url.openConnection();

                connection.setDoInput(true);
                connection.setDoOutput(true);
                connection.setRequestMethod("POST");
                connection.setRequestProperty("accept", "*/*");
                connection.setRequestProperty("content-type", "text/plain;charset=UTF-8");
                connection.setRequestProperty("user-Agent", "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.95 Safari/537.11");
                OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream(), "UTF-8");
                writer.write(payload);
                writer.close();
                BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
                while ((line = br.readLine()) != null) {
                        jsonString.append(line);
                }
                br.close();
                connection.disconnect();
                System.out.println(jsonString.toString());
            } catch (Exception e) {
                    throw new RuntimeException(e.getMessage());
            }
            URL url1 = new URL("https://alphadraft.com/api/ui/contest/getloadinfo/");
            URLConnection con1 = url1.openConnection();
            con1.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.73 Safari/537.36");
            con1.connect();
            InputStream is1 =con1.getInputStream();
            BufferedReader br1 = new BufferedReader(new InputStreamReader(is1));


                System.out.println(br1.readLine());
        }
    }

然而,错误信息

  

{“错误”:“登录失败”}   {“error”:“未经过身份验证”}

仍会弹出我的输出。如果有人能解释为什么这不起作用,我将非常感激。

1 个答案:

答案 0 :(得分:0)

JSON格式请求引号标记属性名称和值,因此在您的情况下应该是: String payload="{\"email_address\" : \"(EMAILHERE)\", \"password\" : \"(PASSWORDHERE)\"}";