Question

Form POST后，Inner Object ExtraData为NULL。我无法将对象传递给Controller。需要帮助来弄清楚这里有什么问题。

我的模特

 public class TestModel
{
    public int ClaimNumber { get; set; }
    public string Key { get; set; }

    public string SaveMessage { get; set; }
    public bool UserAuthorizedEdit { get; set; }

    public ExtraDataModel EData { get; set; }
}

public class ExtraDataModel
{
    public int ID { get; set; }
    public string Code { get; set; }

    public string Desc { get; set; }
}

我的观点

<h2>View1</h2>
@using (Html.BeginForm("SaveDetails", "SaveData", Model, FormMethod.Post, new { @id = "RenderProviderVForm", target = "_blank" }))
            {
<table>
    <tr>
        <td>  @Html.TextBoxFor(model => model.ClaimNumber)</td>
    </tr>
    <tr>
        <td>  @Html.DisplayFor(model => model.Key)</td>
    </tr>
    <tr>
        <td>  @Html.TextBoxFor(model => model.SaveMessage)</td>
    </tr>    
    <tr>
        <td>  @Html.TextBoxFor(model => model.EData.ID)</td>
    </tr>
    <tr>
        <td>  @Html.TextBoxFor(model => model.EData.Code)</td>
    </tr>
    <tr>
        <td>  @Html.TextBoxFor(model => model.EData.Desc)</td>
    </tr>
    <tr>
        <td>
            <button type="submit" class="link-button" value="submit">@Model.ClaimNumber</button>            
        </td>
    </tr>
</table>
}

我的控制器

[HttpPost]
    public void SaveDetails(TestModel tm)
    {
        if (ModelState.IsValid)
        {
            //Save Code
        }
        else
        {
            System.Diagnostics.Debug.Write(ModelState);
        }

    }

ModelState上的错误说：

System.InvalidOperationException：参数转换类型＆＃39; System.String＆＃39;输入＆＃39; MvcApplication2.Models.ExtraDataModel＆＃39;失败，因为没有类型转换器可以在这些类型之间进在System.Web.Mvc.ValueProviderResult.ConvertSimpleType（CultureInfo culture，Object value，Type destinationType）在System.Web.Mvc.ValueProviderResult.UnwrapPossibleArrayType（CultureInfo culture，Object value，Type destinationType）在System.Web.Mvc.ValueProviderResult.ConvertTo（Type type，CultureInfo culture）在System.Web.Mvc.ValueProviderResult.ConvertTo（类型类型）在System.Web.Mvc.DefaultModelBinder.ConvertProviderResult（ModelStateDictionary modelState，String modelStateKey，ValueProviderResult valueProviderResult，Type destinationType）}

我现在遇到了这个例外：

The parameter conversion from type 'System.String' to type 'MvcApplication2.Models.ExtraDataModel' failed because no type converter can convert between these types.

以下是生成的HTML

<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8" />
    <meta name="viewport" content="width=device-width" />
    <title>View1</title>
    <link href="/Content/site.css" rel="stylesheet"/>

    <script src="/Scripts/modernizr-2.6.2.js"></script>

</head>
<body>


<h2>View1</h2>
<form action="/SaveData/SaveDetails?ClaimNumber=123456&amp;Key=40e686ca-1176-4d45-a1dd-33b79b3a9764&amp;SaveMessage=Save%20Me&amp;UserAuthorizedEdit=True&amp;EData=MvcApplication2.Models.ExtraDataModel" id="RenderProviderVForm" method="post" target="_blank"><table>
    <tr>
        <td>  <input data-val="true" data-val-number="The field ClaimNumber must be a number." data-val-required="The ClaimNumber field is required." id="ClaimNumber" name="ClaimNumber" type="text" value="123456" /></td>
    </tr>
    <tr>
        <td>  <input id="Key" name="Key" type="text" value="40e686ca-1176-4d45-a1dd-33b79b3a9764" /></td>
    </tr>
    <tr>
        <td>  <input id="SaveMessage" name="SaveMessage" type="text" value="Save Me" /></td>
    </tr>    
    <tr>
        <td>  <input data-val="true" data-val-number="The field ID must be a number." data-val-required="The ID field is required." id="EData_ID" name="EData.ID" type="text" value="888888" /></td>
    </tr>
    <tr>
        <td>  <input id="EData_Code" name="EData.Code" type="text" value="CD" /></td>
    </tr>
    <tr>
        <td>  <input id="EData_Desc" name="EData.Desc" type="text" value="DVD" /></td>
    </tr>
    <tr>
        <td>
            <button type="submit" class="link-button" value="submit">123456</button>            
        </td>
    </tr>
</table>
</form>

    <script src="/Scripts/jquery-1.8.2.js"></script>


</body>
</html>

现在，如果我必须在表单上编辑并仅发布 ExtraDataModel 值，我应该做些什么修改。

MVC POST复杂对象为NULL

0 个答案: