Question

我正在试图弄清楚如何获取字符串中的字符顺序。当字母首次作为第一个订单出现时也应该考虑到例如：

getText()

有一种简单的方法吗？

Answer 1

可能是这样的：

def ranker(s):
    ranked = sorted(range(len(s)),key=lambda x: (s[x], x))
    d = dict(zip(ranked, range(len(ranked))))
    return [d[i]+1 for i in range(len(s))]

给了我

>>> ranker("abc")
[1, 2, 3]
>>> ranker("dfe")
[1, 3, 2]
>>> ranker("xef")
[3, 1, 2]
>>> ranker("aba")
[1, 3, 2]
>>> ranker("bba")
[2, 3, 1]
>>> ranker("bbac")
[2, 3, 1, 4]

Answer 2

这是@ CoryKramer的答案的替代方案。它不使用元组上的index方法，而是使用字典查找，对于长字符串可能更快。

def order(s):
    ordered = sorted(s)
    position = {c: i for i, c in enumerate(ordered)}
    return [position[c]+1 for c in s]

>>> order('abc')
[1, 2, 3]
>>> order('dfe')
[1, 3, 2]
>>> order('xef')
[3, 1, 2]

Answer 3

file = open("Class A.txt", "r")
f2 = file.read().split('|')
file.close()
print(f2)

Answer 4

这是我的代码，试试吧

s = 'badca'
order = []

for x in range(len(s)):
    order.append(0)
print(order)

for i in range(len(s)):
    for j in range(len(s)):
        if i == j:
            order[i] = order[i] + 1
        elif i != j:
            if s[i] > s[j]:
                order[i] = order[i] + 1
            elif (s[i] == s[j]) and (j > i):
                order[j] = order[j] + 1



print(order)

获取字符串python中的字母顺序

4 个答案: