我有两个对象如下:
public class Item
{
public int ItemId {get;set;}
public string ItemName {get;set;}
public List<Tag> ItemTags {get;set;}
public DateTime DateCreated {get;set;}
}
public class Tag
{
public int TagId {get;set;}
public string TagName {get;set;}
}
这些是LINQ-to-SQL对象,因此ItemTags将是一个EntitySet。
我正在尝试执行搜索查询,其中用户可以提供以逗号分隔的标记列表作为搜索过滤器。
如何将我的项目列表过滤到包含逗号分隔列表中所有标记的项目。
EDIT2
e.g.
Item1 has tags of Apple, Banana, Orange
Item2 has tags of Banana, Orange
Item3 has tags of Pineapple, Orange
If the tag filter is "Banana, Orange" I need the results to be Item1 and Item2.
/ EDIT2
这是我到目前为止所尝试的:
string tags = "Manchester United,European Cup,2008";
List<string> tagsList = tags.Trim().ToLower()
.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries)
.Distinct(StringComparer.CurrentCultureIgnoreCase)
.ToList();
List<Item> itemList = ItemRepository.FetchAll();
var query = itemList
.OrderByDescending(p => p.DateCreated)
.ToList();
if (tagsList.Count() > 0)
{
query = query
.Where(p => p.ItemTags
.Select(q => q.TagName.ToLower())
.All(r => tagsList.Contains(r)))
.ToList();
}
但是,这似乎不起作用。关于我做错了什么想法吗?
EDIT1:标签被修剪并且是“小写的”。
答案 0 :(得分:1)
这是因为您将项目中的标记设置为小写,而不是搜索的标记。
通过这种修改,它应该有效:
List<string> tagsList = tags
.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries)
.Select(s => s.ToLower())
.Distinct()
.ToList();
请尝试改为:
query =
(from item in query
let itemTags = p.ItemTags.Select(it => it.TagName.ToLower())
where tags.All(t => itemTags.Contains(t))
select item).ToList();
更新:这是一个带有lambda语法的版本。由于临时匿名类型,它非常难看,但这就是let
子句转换为lambda ...
query =
query.Select(item => new { item, itemTags = item.ItemTags.Select(it => it.TagName.ToLower()) })
.Where(x => tagsList.All(t => x.itemTags.Contains(t)))
.Select(x => x.item)
.ToList();
答案 1 :(得分:0)
我认为你需要做这样的事情:
var query = itemList.OrderByDescending(p => p.DateCreated).ToList();
var results = query.Where(i => i.ItemTags
.All(it => tagsList.Contains(it.TagName.ToLower())));
然后results
应该是匹配项目的列表。
PS。您的代码显示您从存储库中获取itemList
作为列表,然后然后按创建日期排序。这意味着数据库中没有进行排序。一旦你将某些东西变成了List,你就会放弃延迟执行的好处,因为你会将整个集合带回内存。
编辑:这是证明它在Linq to Objects中的测试代码:
public class Item
{
public int ItemId { get; set; }
public string ItemName { get; set; }
public List<Tag> ItemTags { get; set; }
public DateTime DateCreated { get; set; }
}
public class Tag
{
public int TagId { get; set; }
public string TagName { get; set; }
}
class Program
{
static void Main(string[] args)
{
RunTags();
}
private static void RunTags()
{
Item i1 = new Item()
{
ItemId = 1,
ItemName = "Item1",
ItemTags = new List<Tag>() { new Tag { TagId = 1, TagName = "2008" }, new Tag { TagId = 2, TagName = "Donkey" } }
};
Item i2 = new Item()
{
ItemId = 2,
ItemName = "Item2",
ItemTags = new List<Tag>() { new Tag { TagId = 4, TagName = "Cat" }, new Tag { TagId = 2, TagName = "Donkey" }, new Tag { TagId = 3, TagName = "Seattle" } }
};
Item i3 = new Item()
{
ItemId = 3,
ItemName = "Item3",
ItemTags = new List<Tag>() { new Tag { TagId = 523, TagName = "Manchester united" }, new Tag { TagId = 10, TagName = "European Cup" }, new Tag { TagId = 1, TagName = "2008" } }
};
Item i4 = new Item()
{
ItemId = 4,
ItemName = "Item4",
ItemTags = new List<Tag>() { new Tag { TagId = 05, TagName = "Banana" }, new Tag { TagId = 140, TagName = "Foo" }, new Tag { TagId = 4, TagName = "Cat" } }
};
Item i5 = new Item()
{
ItemId = 5,
ItemName = "Item5",
ItemTags = new List<Tag>() { new Tag { TagId = 05, TagName = "Banana" }, new Tag { TagId = 140, TagName = "Foo" } }
};
List<Item> itemList = new List<Item>() { i1, i2, i3, i4, i5 };
string tags = "Manchester United,European Cup,2008";
List<string> tagsList = tags.Trim().ToLower()
.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries)
.Distinct(StringComparer.CurrentCultureIgnoreCase)
.ToList();
var query = itemList
.OrderByDescending(p => p.DateCreated).ToList();
var results = query.Where(i => i.ItemTags.All(it => tagsList.Contains(it.TagName.ToLower())));
foreach (var item in results)
{
Console.WriteLine(item.ItemName); // Should return "Item3"
}
Console.ReadLine();
}
如果你想匹配Item的ItemTag列表中的任何标签,那么只需将All改为Any。
var results = query.Where(i => i.ItemTags.Any(it => tagsList.Contains(it.TagName.ToLower())));