这是我的代码:
use TSQL2012
select
emp.empid, emp.firstname, emp.mgrid,
manager.firstname as manager_name,
sum(unique(emp.mgrid)) as Total
from
HR.Employees AS emp, HR.Employees as manager
where
emp.mgrid = manager.empid
go
我应该得到的结果是:
empid firstame mgrid manager_name Total
1 2 Don 1 Sara 1
2 3 Judy 2 Don 2
3 4 Yael 3 Judy 2
4 5 Sven 2 Don 2
5 6 Paul 5 Sven
6 7 Russell 5 Sven
7 8 Maria 3 Judy
8 9 Zoya 5 Sven
我无法获得最后一栏(总计)。任何帮助将不胜感激
答案 0 :(得分:1)
这样做的一种方法是使用CROSS APPLY
:
select emp.empid, emp.firstname, emp.mgrid, manager.firstname as manager_name,
x.cnt as Total
from Employees AS emp
inner join Employees as manager on emp.mgrid = manager.empid
cross apply (
select count(*)
from Employees AS e
where e.mgrid = emp.mgrid) AS x(cnt)
修改强>
您也可以这样使用CTE
:
;With C as (
select b.mgrid, count(*) as Total
from Employees as b
group by mgrid
)
select emp.empid, emp.firstname, emp.mgrid, manager.firstname as manager_name,
Total
from Employees AS emp
inner join Employees as manager on emp.mgrid = manager.empid
inner join C on emp.mgrid = C.mgrid