Question

问题是登录和所有事情都很有效，除了记住我的逻辑。未设置cookie，并且数据库中没有插入任何行。

这是安全配置类。

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.web.authentication.rememberme.JdbcTokenRepositoryImpl;
import org.springframework.security.web.authentication.rememberme.PersistentTokenRepository;

import javax.sql.DataSource;

/**
 * Spring security configurations.
 */
@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
    @Autowired
    private DataSource dataSource;

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
                // Authorize all requests
                .authorizeRequests()
                    // Allow only admins to access the administration pages
                    .antMatchers("/admin/**").access("hasRole('ADMIN')")
                    // Allow any one to access the register and the main pages only alongside
                    // the resources files that contains css and javascript files
                    .antMatchers("/resources/**", "/register", "/").permitAll()
                    // Authenticate any other request
                    .anyRequest().authenticated()
                    .and()
                // Set up the login form.
                .formLogin()
                    //.successHandler(successHandler())
                    .loginPage("/login")
                    .usernameParameter("email").passwordParameter("password")
                    .permitAll()
                    .and()
                // Enable remember me cookie and persistence storage
                .rememberMe()
                    // Database token repository
                    .tokenRepository(persistentTokenRepository())
                    // Valid for 20 days
                    .tokenValiditySeconds(20 * 24 * 60 * 60)
                    .rememberMeParameter("remember-me")
                    .and()
                // Log out handler
                .logout()
                    .permitAll()
                    .and()
                // Enable Cross-Site Request Forgery
                .csrf();
    }

    @Bean
    public PersistentTokenRepository persistentTokenRepository() {
        JdbcTokenRepositoryImpl db = new JdbcTokenRepositoryImpl();
        db.setDataSource(dataSource);
        return db;
    }

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        // Provide database authentication and swl queries to fetch the user's data..
        auth.jdbcAuthentication().dataSource(dataSource)
                .usersByUsernameQuery("select email, password, enabled from users where email=?")
                .authoritiesByUsernameQuery("select us.email, ur.role from users us, " +
                        " roles ur where us.role_id=ur.id and us.email=?");
    }
}

这是令牌持久性的数据库表

CREATE TABLE persistent_logins (
    username VARCHAR(254) NOT NULL,
    series VARCHAR(64) NOT NULL,
    token VARCHAR(64) NOT NULL,
    last_used TIMESTAMP NOT NULL,
    PRIMARY KEY (series)
);

Answer 1

Spring Security附带了PersistentTokenRepository的2个实现：JdbcTokenRepositoryImpl和InMemoryTokenRepositoryImpl。我在我的应用程序中使用Hibernate，我使用Hibernate而不是使用JDBC创建自定义实现。

@Repository("tokenRepositoryDao")
@Transactional
public class HibernateTokenRepositoryImpl extends AbstractDao<String, PersistentLogin>
        implements PersistentTokenRepository {

    static final Logger logger = LoggerFactory.getLogger(HibernateTokenRepositoryImpl.class);

    @Override
    public void createNewToken(PersistentRememberMeToken token) {
        logger.info("Creating Token for user : {}", token.getUsername());
        PersistentLogin persistentLogin = new PersistentLogin();
        persistentLogin.setUsername(token.getUsername());
        persistentLogin.setSeries(token.getSeries());
        persistentLogin.setToken(token.getTokenValue());
        persistentLogin.setLast_used(token.getDate());
        persist(persistentLogin);

    }

    @Override
    public PersistentRememberMeToken getTokenForSeries(String seriesId) {
        logger.info("Fetch Token if any for seriesId : {}", seriesId);
        try {
            Criteria crit = createEntityCriteria();
            crit.add(Restrictions.eq("series", seriesId));
            PersistentLogin persistentLogin = (PersistentLogin) crit.uniqueResult();

            return new PersistentRememberMeToken(persistentLogin.getUsername(), persistentLogin.getSeries(),
                    persistentLogin.getToken(), persistentLogin.getLast_used());
        } catch (Exception e) {
            logger.info("Token not found...");
            return null;
        }
    }

    @Override
    public void removeUserTokens(String username) {
        logger.info("Removing Token if any for user : {}", username);
        Criteria crit = createEntityCriteria();
        crit.add(Restrictions.eq("username", username));
        PersistentLogin persistentLogin = (PersistentLogin) crit.uniqueResult();
        if (persistentLogin != null) {
            logger.info("rememberMe was selected");
            delete(persistentLogin);
        }

    }

    @Override
    public void updateToken(String seriesId, String tokenValue, Date lastUsed) {
        logger.info("Updating Token for seriesId : {}", seriesId);
        PersistentLogin persistentLogin = getByKey(seriesId);
        persistentLogin.setToken(tokenValue);
        persistentLogin.setLast_used(lastUsed);
        update(persistentLogin);
    }

}

Answer 2

我转载了同样的问题。使用调试功能，我检查了loginSuccess()方法的AbstractRememberMeServices类。

内部逻辑就像：

public final void loginSuccess(HttpServletRequest request, HttpServletResponse response, Authentication successfulAuthentication) {
    if (!this.rememberMeRequested(request, this.parameter)) {
        this.logger.debug("Remember-me login not requested.");
    } else {
        this.onLoginSuccess(request, response, successfulAuthentication);
    }
}

原来，我没有在用户登录时被标记为Remember Me标记，所以我无法调用onLoginSuccess()方法，如果不能使用其他方法，则会陷入困境。 >

标记完标记后，我可以保留令牌和cookie。

Spring安全令牌持久性存储无法正常工作

2 个答案: