Question

我有一个短信模板，如下所示

用户：XXXXXXXXXXXXXXXXXX，电话：XXXXXXXXXX，Loc：XXXXXXXXXXXXXXXXXXXX，区域：XXXXXXXXXXXXXXXXXXXX，为您添加了送货上门服务。请查看详情

其中XXXXXX需要填充动态值

我试过这种方式，如下所示

但是当我运行程序时，我得到的输出是

User: Kiran, Ph: 11111111111111, Loc: KiranXX, Area: KiranXX, added you for Home Delivery. Please review details

最后添加XX 这是我的程序

import java.net.UnknownHostException;

import org.apache.log4j.Logger;

public class Test {
    final static Logger logger = Logger.getLogger(Test.class);

    public static void main(String args[]) throws UnknownHostException
    {

        String user = "Kiran";
        String phone = "11111111111111";
        String loc = "my location";
        String area = "my area";


        String message = "User: XXXXXXXXXXXXXXXXXX, Ph: XXXXXXXXXX, Loc: XXXXXXXXXXXXXXXXXXXX, Area: XXXXXXXXXXXXXXXXXXXX, added you for Home Delivery. Please review details\r\n" + 
                "";

        message = message.replace("XXXXXXXXXXXXXXXXXX", user);
        message = message.replace("XXXXXXXXXX", phone);
        message = message.replace("XXXXXXXXXXXXXXXXXXXX", loc);
        message = message.replace("XXXXXXXXXXXXXXXXXXXX", area);

        System.out.println(message);


    }

}

你能告诉我如何解决这个问题吗？

Answer 1

你应该用这个：

String template = "User: %s, Ph: %s, Loc: %s, Area: %s, added you for Home Delivery. Please review details\r\n";

String result = String.format(template, user, phone, loc, area);

Javadoc of String.format() here

Answer 2

首先替换肯定是错误的。

我会像这样编码：

修改

message = message.replace("User: XXXXXXXXXXXXXXXXXX", "User: " +user);

Answer 3

我的建议是：

message = message.replace( "User:\\s+X+", "User: " + user );

这将：

忽略User：和X的
忽略有多少X，只吃掉他们每个人

在这种情况下如何正确使用String替换？

3 个答案: