使用此代码仅打开特殊号码的聊天但文字不是共享。我该怎么做?
public class MainActivity extends AppCompatActivity {
Button Wa;
String id = "+919000000000";
EditText txt;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
txt = (EditText)findViewById(R.id.editText);
Wa = (Button)findViewById(R.id.btn_whatsapp);
Wa.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Uri uri = Uri.parse("smsto:" + id);
Intent waIntent = new Intent(Intent.ACTION_SENDTO,uri);
String text = "testing message";
waIntent.setPackage("com.whatsapp");
if (waIntent != null) {
waIntent.putExtra(Intent.EXTRA_TEXT, text);
startActivity(Intent.createChooser(waIntent, text));
} else {
Toast.makeText(getApplicationContext(), "WhatsApp not found", Toast.LENGTH_SHORT)
.show();
}
}
});
}
答案 0 :(得分:1)
由于您尝试将其作为"smsto:"
来实现,因此类型"text/plain"
会对您有所帮助。如果它没有帮助,请尝试额外为"sms_body"
。
Uri uri = Uri.parse("smsto:" + id);
Intent waIntent = new Intent(Intent.ACTION_SENDTO,uri);
String text = "testing message";
waIntent.setPackage("com.whatsapp");
if (waIntent != null) {
waIntent.setType("text/plain");
//waIntent.putExtra(Intent.EXTRA_TEXT, text);
waIntent.putExtra("sms_body", text);
startActivity(Intent.createChooser(waIntent, text));
} else {
Toast.makeText(getApplicationContext(), "WhatsApp not found", Toast.LENGTH_SHORT)
.show();
}
答案 1 :(得分:0)
请完成此stackoverflow链接
似乎 WhatsApp 仍然没有支持这个胎儿。 您只能使用以下代码
打开特定号码的聊天记录
try {
Uri mUri = Uri.parse("smsto:+98xxxxxxxx");
Intent mIntent = new Intent(Intent.ACTION_SENDTO, mUri);
mIntent.setPackage("com.whatsapp");
// mIntent.putExtra("sms_body", "My body");
mIntent.putExtra(Intent.EXTRA_TEXT, "This is my text to send.");
startActivity(mIntent);
} catch (Exception e) {
// alert WhatsApp in not installed
}
答案 2 :(得分:0)
尝试这样的事情:
public class MainActivity extends AppCompatActivity {
Button Wa;
String id = "+919000000000";
EditText txt;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
txt = (EditText)findViewById(R.id.editText);
Wa = (Button)findViewById(R.id.btn_whatsapp);
Wa.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
PackageManager pm=getPackageManager();
try {
Uri uri = Uri.parse("smsto:" + number);
Intent i = new Intent(Intent.ACTION_SENDTO, uri);
waIntent.setType("text/plain");
String text = "testing message";
PackageInfo info=pm.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
waIntent.setPackage("com.whatsapp");
waIntent.putExtra(Intent.EXTRA_TEXT, text);
startActivity(Intent.createChooser(waIntent, text));
}
catch (NameNotFoundException e) {
Toast.makeText(this, "WhatsApp not found", Toast.LENGTH_SHORT).show();
}
}
});
}
}
答案 3 :(得分:0)
来自Here
的回答早些时候,这是不可能的,但自2015年5月更新以来。结帐:
try{
PackageInfo info = pm.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
String sendString = "some random string";
sendIntent.setPackage("com.whatsapp");
sendIntent.putExtra(Intent.EXTRA_TEXT, sendString);
sendIntent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(file));
sendIntent.setType("image/*");
startActivity(sendIntent);
} catch (Exception e){
// some code
}
这里的PackageInfo行只是检查是否安装了WhatsApp。如果没有,它会抛出异常。如果你想做一个普通的共享(和setPackage),你可以忽略它。
另外。重要的是,您要共享的媒体必须在本地存储上公开。
<强>更新强>
发送给特定联系人
Uri uri = Uri.parse("smsto:" + "<CONTACT_NUMBER>");
Intent i = new Intent(Intent.ACTION_SENDTO, uri);
i.putExtra(Intent.EXTRA_TEXT, whatsAppMessage);
现在允许行动发送至。