如何从php

Question

我需要编写一个PHP函数来删除URL中的文件名。 [我不想简单地删除网址的最后一部分。因为某些网址会像http://www.examples.com/sample这样＆＃34;样本＆＃34;不能是一个文件。我只想删除文件名。

In. -> http://www.inforge.in/ongoing-works/main_project/index.html  
Out -> http://www.inforge.in/ongoing-works/main_project/

In. -> http://www.inforge.in/ongoing-works/main_project/
Out -> http://www.inforge.in/ongoing-works/main_project/

In. -> http://www.inforge.in/ongoing-works/main_project
Out -> http://www.inforge.in/ongoing-works/main_project/

我认为解决方法是检查是否有＆＃39;。＆＃39; [dot]出现在最后一个＆＃39; /＆＃39;之后。如果是这样，请删除最后一个＆＃39; /＆＃39;之后的所有内容。但是没有得到用PHP编写它的逻辑

我无法简单地检查是否存在＆＃39; .html＆＃39;，因为文件名可以是.php，.jpg，.jsp或类似的东西

Answer 1

function stripFile($in){
    $pieces = explode("/", $in); // split the URL by /
    if(count($pieces) < 4) return $in . "/";
    if(strpos(end($pieces), ".") !== false){ // we got a filename at the end
        array_pop($pieces); // remove the filename
    }elseif(end($pieces) !== ""){ // it ends with a name without an extension, i.e. a directory
        $pieces[] = ""; // when $pieces is imploded, a "/" and then this "" will be appended
    }
    // else, already ends with a slash
    return implode("/", $pieces);
}

Answer 2

function removeFile($url){
    $pieces = explode("/", $url); // split the URL by /
    if(count($pieces) < 4) return $url. "/";
    if(strpos(end($pieces), ".") !== false){ // we got a filename at the end
        array_pop($pieces); // remove the filename
    }elseif(end($pieces) !== ""){ // it ends with a name without an extension, i.e. a directory
        $pieces[] = ""; // when $pieces is imploded, a "/" and then this "" will be appended
    }
    // else, already ends with a slash
    return implode("/", $pieces);
}

Answer 3

$lks = pathinfo("http://www.inforge.in/ongoingworks/main_project/index.html");
echo $lks['dirname'];