我有一个简单的data.frame,包含两个变量title和base64。我需要将这个data.frame转换为XML格式。例如,我的数据是什么样的..
str(df)
'data.frame': 2 obs. of 2 variables:
$ title : chr "Page One" "Page Two"
$ base64: chr "Very Long String thats a base64 character" "Very Long String thats a base64 character"
dput(DF) 结构(list(page = c(“Page One”,“Page Two”),base64 = c(“非常长的字符串,表示base64字符”, “非常长的字符串,其中包含base64字符”)),。Name = c(“page”, “base64”),row.names = 1:2,class =“data.frame”)
我需要输出一个格式看起来像这样的XML文件......
<report type="enchanced">
<pages>
<page>
<title>Page One</title>
<page> *** long base64 string *** </page>
</page>
<page>
<title>Page Two</title>
<page> *** long base64 string *** </page>
</page>
</pages>
</report>
我一直在试验R中的XML包,甚至发现这个功能似乎应该可行,但我无法弄明白。任何帮助是极大的赞赏。
library(XML)
convertToXML <- function(df,name) {
xml <- xmlTree("report")
xml$addNode(name, close=FALSE)
for (i in 1:nrow(df)) {
xml$addNode("page", close=FALSE)
for (j in names(df)) {
xml$addNode(j, df[i, j])
}
xml$closeTag()
}
xml$closeTag()
return(xml)
}
tr = convertToXML(df,"pages")
cat(saveXML(tr$page())) ## suppose to looks good
答案 0 :(得分:8)
关于this answer,我做
data<- structure(list(page = c("Page One", "Page Two"), base64 = c("Very Long String thats a base64 character", "Very Long String thats a base64 character")), .Names = c("page", "base64"), row.names = 1:2, class = "data.frame")
names(data) <- c("title", "page")
library(XML)
xml <- xmlTree()
# names(xml)
xml$addTag("report", close=FALSE, attrs=c(type="enhanced"))
xml$addTag("pages", close=FALSE)
for (i in 1:nrow(data)) {
xml$addTag("page", close=FALSE)
for (j in names(data)) {
xml$addTag(j, data[i, j])
}
xml$closeTag()
}
xml$closeTag()
xml$closeTag()
cat(saveXML(xml))
# <?xml version="1.0"?>
#
# <report type="enhanced">
# <pages>
# <page>
# <title>Page One</title>
# <page>Very Long String thats a base64 character</page>
# </page>
# <page>
# <title>Page Two</title>
# <page>Very Long String thats a base64 character</page>
# </page>
# </pages>
# </report>