我有一堆控制器,如:
@RestController
public class AreaController {
@RequestMapping(value = "/area", method = RequestMethod.GET)
public @ResponseBody ResponseEntity<Area> get(@RequestParam(value = "id", required = true) Serializable id) { ... }
}
我需要拦截所有到达他们的请求,
我像这个例子一样创建了一个拦截器:
http://www.mkyong.com/spring-mvc/spring-mvc-handler-interceptors-example/
但它永远不会进入:(
因为我只使用注释,所以我没有XML来定义拦截器, 我发现它的设置如下:
@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "com.test.app")
public class AppConfig extends WebMvcConfigurerAdapter {
@Bean
public ControllerInterceptor getControllerInterceptor() {
ControllerInterceptor c = new ControllerInterceptor();
return c;
}
@Override
public void addInterceptors(InterceptorRegistry registry) {
registry.addInterceptor(getControllerInterceptor());
super.addInterceptors(registry);
}
}
我做错了什么或者我错过了什么?
答案 0 :(得分:3)
您的Interceptor
类ControllerInterceptor
不是应用程序上下文托管bean。确保在ControllerInterceptor上放置@Component
注释,并将其包添加到@ComponentScan
。所以,假设您的ControllerInterceptor
位于com.xyz.interceptors包中,如:
package com.xyz.interceptors; //this is your package
@Component //put this annotation here
public class ControllerInterceptor extends HandlerInterceptorAdapter{
// code here
}
,您的AppConfig变为:
@ComponentScan(basePackages = { "com.test.app", "com.xyz.interceptors" })
public class AppConfig extends WebMvcConfigurerAdapter {
// ...
}
答案 1 :(得分:2)
定义拦截器如:
<mvc:interceptors>
<bean class="com.test.ControllerInterceptor" />
</mvc:interceptors>
我很确定你也可以在纯java中定义它,但这很有效,
答案发现于: http://viralpatel.net/blogs/spring-mvc-interceptor-example/
答案 2 :(得分:1)
可能您缺少映射
strsplit(gsub(';[a-z]+', '', d), ',')
#[[1]]
#[1] "aa" "bb" "cc" "dd" "ee" "ff"
#[[2]]
#[1] "gg" "hh" "ii" "jj"
据我所知,你不必使用
registry.addInterceptor(getControllerInterceptor()).addPathPatterns("/**");