Question

def parse_shot_success(string):
    """
    Determine if the shot was successful.
    Input:
        string: a string to be analyzed
    Returns:
        "scores" or "misses" or "not a shot" based on
        the shot success.
    """
    pp = re.compile("(scores|misses|blocks)")
    match = pp.search(string)
    if match.group(1) == "scores":
        return "scores"
    elif match.group(1) == ("blocks|misses"):
        return "misses"
    else:
        return "not a shot"

嗨，我想回复＆＃34;未命中＆＃34;或＆＃34;得分＆＃34;基于玩家是否在字符串中得分或错过，以便parse_shot_success("Johnson blocks Lebron's shot")将返回未命中。我想我必须使用for loop，但我不确定如何将其合并到我的代码中。你能帮我谢谢。

Answer 1

如果你真的想要使用正则表达式：

def parse_shot_success(string):
    pp = re.compile("(scores|misses|blocks)")
    match = pp.search(string)

    if not match:
        # https://docs.python.org/dev/library/re.html#re.search
        # "Return None if no position in the string matches the pattern"
        return "not a shot"
    elif match.group(1) == "scores":
        return "scores"
    elif match.group(1) in ("blocks", "misses"):
        return "misses"
    else:
        raise AssertionError

但是这个问题可以通过其他方式轻松解决：

def parse_shot_success(string):
    if 'scores' in string:
        return 'scores'
    elif 'blocks' in string or 'misses' in string:
        return 'misses'
    else:
        return 'not a shot'

或者：

def parse_shot_success(string):
    words = [
        # (word, return value)
        ('scores', 'scores'),
        ('blocks', 'misses'),
        ('misses', 'misses'),
    ]

    for word, result in words:
        if word in string:
            return result

    return 'not a shot'

您有一些未考虑的问题：

如果我给你字符串"SCORE"（大写）？
如果有名字为＆＃34; blocksmith＆＃34;的玩家怎么办？（包含单词＆＃34; blocks＆＃34;）？这种情况下使用正则表达式可能是最简单的方法。

搜索字符串并将其转换为另一个字符串python

1 个答案: