Question

如何在数据库中插入此表单的值？

<tr>
    <td>1. Do you feel well and healthy?</label></td>
    <input type="hidden" name="question" value="1. Do you feel well and healthy?">
    <td><input type="radio" name="answer" value="Yes" checked></td>
    <td><input type="radio"  name="answer" value="No"></td>
    <td><input type="text" name="remarks"></td>
</tr>
<tr>
    <td><ul><li>Have any flu or cold?</li></ul></td>
    <input type="hidden" name="question" value="Have any flu or cold?">
    <td><input type="radio" name="answer" value="Yes" checked> </td>
    <td><input type="radio"  name="answer" value="No"></td>
    <td><input type="text" name="remarks"></td>
</tr>

因为当我要将这些数据插入数据库时，它只插入第二个表行中的最后一个值“有烟道”....

$medical = new MedicalHistory;
$medical->username = $value;
$medical->question = $data['question'];
$medical->answer   = $data['answer'];
$medical->remarks  = $data['remarks1'];
$medical->save();

我使用laravel作为框架

Answer 1

仅插入第二个表单的原因是因为您正在为字段重复使用相同的名称。

一种解决方案是为所有字段提供唯一的名称（单选按钮对除外）。

更好的解决方案是制作阵列输入，我已经快速搜索了你并想出了这个：How to get form input array into PHP array

您应该将代码修改为数组变量，因此如果您想保存多个问题，请在两个问题字段中使用名称'question []'而不是'question'。

前端表示例：

<tr>
    <td>1. Do you feel well and healthy?</label></td>
    <input type="hidden" name="question[]" value="1. Do you feel well and healthy?">
    <td><input type="radio" name="answer[0]" value="Yes" checked></td>
    <td><input type="radio"  name="answer[0]" value="No"></td>
    <td><input type="text" name="remarks[]"></td>
</tr>
<tr>
    <td><ul><li>Have any flu or cold?</li></ul></td>
    <input type="hidden" name="question[]" value="Have any flu or cold?">
    <td><input type="radio" name="answer[1]" value="Yes" checked> </td>
    <td><input type="radio"  name="answer[1]" value="No"></td>
    <td><input type="text" name="remarks[]"></td>
</tr>

要在PHP逻辑中处理数据的新格式，您应该执行以下操作：

$question = $_POST['question'];
$answer = $_POST['answer'];
$remark = $_POST['remarks'];

foreach( $question as $key => $q ) {
    print "The question is ".$q.", answer is ".$answer[$key].
          ", and remarks are ".$remark[$key].". Thank you\n";
}

由于您要保存数据，您应该执行以下操作：

$value = 'idk_where_you_assign_names';
$question = $_POST['question'];
$answer = $_POST['answer'];
$remark = $_POST['remarks'];

foreach( $question as $key => $q ) {
    $medical = new MedicalHistory;
    $medical->username = $value;
    $medical->question = $q;
    $medical->answer   = $answer[$key];
    $medical->remarks  = $remark[$key];
    $medical->save();
}

在我编辑之后，它现在应该可以正常工作。

Answer 2

你的表格应该是这样的：

<tr>
    <td>1. Do you feel well and healthy?</label></td>
    <input type="hidden" name="question" value="1. Do you feel well and healthy?">
    <td><input type="radio" name="answer" value="Yes" checked></td>
    <td><input type="radio"  name="answer" value="No"></td>
    <td><input type="text" name="remarks"></td>
</tr>
<tr>
    <td><ul><li>Have any flu or cold?</li></ul></td>
    <input type="hidden" name="question2" value="Have any flu or cold?">
    <td><input type="radio" name="answer2" value="Yes" checked> </td>
    <td><input type="radio"  name="answer2" value="No"></td>
    <td><input type="text" name="remarks2"></td>
</tr>
<?php
$medical = new MedicalHistory;
$medical->username = $value;
$medical->question = $data['question'];
$medical->answer   = $data['answer'];
$medical->remarks  = $data['remarks1'];
$medical->save();

$medical = new MedicalHistory;
$medical->username = $value;
$medical->question = $data['question2'];
$medical->answer   = $data['answer2'];
$medical->remarks  = $data['remarks2'];
$medical->save();
?>

实际上你的表单元素被覆盖了。

由于阿米特

将表单值插入数据库

2 个答案: