复制数组

Question

我正在从我的数据库中返回给我的数组中构建一个新数组。我的原始数组由许多对象组成，并且几个对象可以像这样对象：

object(stdClass)[26]
  public 'id' => string '6' (length=1)
  public 'title' => string 'Something' (length=41)
  public 'excerpt' => string '<p>Something</p>' (length=104)
  public 'content' => string '<p>Lorem Ipsum</p>' (length=18)
  public 'location' => string '' (length=0)
  public 'author' => string '' (length=0)
  public 'date' => string '2015-09-28' (length=10)
  public 'publish' => string '1' (length=1)
  public 'top' => string '0' (length=1)
  public 'post_id' => string '0' (length=1)
  public 'news_image_path' => string '14545819551_gallery.jpg' (length=23)
  public 'news_main_image' => string '0' (length=1)

这个对象的唯一区别在于＆＃34; news_image_path＆＃34;财产和＆＃34; news_main_image＆＃34;属于＆＃34; 0＆＃34;，＆＃34; 1＆＃34;或NULL。根据那个＆＃34; news_main_image＆＃34;我想合并那些相同的对象，我希望只有'news_main_image' => string '1'的那个对象在这个过程中幸存下来，如果没有＆＃39; news_image_path＆＃39;应为NULL或者如果有'news_main_image' => string '0'属性＆＃39; news_image_path＆＃39;也应该为null。

简而言之：

如果'news_main_image' => string '1'则'news_image_path' => string '14545819576_main.jpg'

如果'news_main_image' => string '0'则'news_image_path' => NULL

如果'news_main_image' => NULL则'news_image_path' => NULL

但其他所有财产应保持不变！

我的代码到目前为止，但它覆盖了自己，如果在前一次迭代中设置了news_image_path，则会在其上复制NULL：

foreach ($result as $key => $value)
{   
   if ($value->news_main_image == '1')
   {
       $tmp[$value->id] = $value;
       $tmp[$value->id]->news_image_path = $value->news_image_path;
   }
   elseif ($value->news_main_image == '0')
   {
       // DO SOMETHING HERE that will copy to the new array but it wont copy over the existing $tmp[$value->id]->news_image_path
       $tmp[$value->id] = $value;
       $tmp[$value->id]->news_image_path = NULL;
   }
   else
   {
      $tmp[$value->id] = $value;
   }

}
$result = $tmp;

Answer 1

我略微改进了你的代码并尝试了它，并且工作正常。

    foreach ($itemArray as $item)
    {
       $tmp[$item->id] = $item;

       if ($item->news_main_image == '0'){
           $tmp[$item->id]->news_image_path = NULL;
       }

    }
    $result = $tmp;

但是它应该和你的一样完全没有......

Answer 2

如果我理解你，假设你有一个看起来像这样的对象数组：

array(2) {
  [0]=>
  object(stdClass)#22 (2) {
    //....
    ["news_image_path"]=>
    string(23) "14545819551_gallery.jpg"
    ["news_main_image"]=>
    string(1) "1"
  }
  [1]=>
  object(stdClass)#23 (2) {
    //...
    ["news_image_path"]=>
    string(23) "14545819552_gallery.jpg"
    ["news_main_image"]=>
    int(0)
  }
}

您可以尝试以下代码

 //$o is the array of objects you have
 //$res will be your result array of objects
 $res = array(); 
 foreach ( $o as $a ){
    //$tmp will be your new object
    $tmp = $a; 
    if (! $a->news_main_image ){
        $tmp->news_image_path = null; 
    }
    $res[] = $tmp; 
 }

，您的输出将如下所示

array(2) {
  [0]=>
  object(stdClass)#22 (2) {
    ["news_image_path"]=>
    string(23) "14545819551_gallery.jpg"
    ["news_main_image"]=>
    string(1) "1"
  }
  [1]=>
  object(stdClass)#23 (2) {
    ["news_image_path"]=>
    NULL
    ["news_main_image"]=>
    int(0)
  }
}

希望有所帮助

Answer 3

虽然我讨厌使用两个foreach语句，但这是解决方案。如果有人能写得更好，请告诉我：

        foreach ($result as $key => $value)
        {   
            if ($value->news_main_image == '1')
            {
                $news_image_path[$value->id] = $value->news_image_path;
            }
            else
            {
                $value->news_image_path = NULL;
            }

            $tmp[$value->id] = $value;
        }

        foreach ($news_image_path as $key => $value)
        {
            $tmp[$key]->news_image_path = $value;
        }

        $result = $tmp;