在jetty和tomcat上运行spring hibernate web应用程序

时间:2016-02-05 06:31:33

标签: java hibernate spring-mvc tomcat jetty

我创建了一个spring-hibernate Web应用程序,它在jetty服务器上运行良好。

然而,当我在tomcat上运行它时它成功运行没有错误,但是我无法在Web浏览器上使用该应用程序,Web浏览器上没有任何内容(甚至没有错误)。

以下是详细信息: -

这是应用程序使用jetty服务器成功启动的地方。

  

http://localhost:8080/contacts

这是我为此定义控制器的地方。

@Controller
public class ContactController {

    @Autowired
    private ContactRepository contactRepository;

    @RequestMapping(value = "/contacts", method = RequestMethod.GET)
    public String getContactList(Model model) {
        model.addAttribute("contacts", contactRepository.findAll());
        return "contact/list";
    }

}

web.xml文件。

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">


    <servlet>
        <servlet-name>spring</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>spring</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>


    <servlet-mapping>
        <servlet-name>jsp</servlet-name>
        <url-pattern>/view/*</url-pattern>
    </servlet-mapping>

    <filter>
        <filter-name>openEntityManagerInViewFilter</filter-name>
        <filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
        <init-param>
            <param-name>entityManagerFactoryBeanName</param-name>
            <param-value>entityManagerFactory</param-value>
        </init-param>
    </filter>

    <filter-mapping>
        <filter-name>openEntityManagerInViewFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

</web-app>

下面是spring-servlet.xml文件

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">

    <mvc:annotation-driven />
    <context:component-scan base-package="com.marakana.contacts.controllers" />

    <bean
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/view/" />
        <property name="suffix" value=".jsp" />
    </bean>
</beans>

1 个答案:

答案 0 :(得分:1)

也许对于tomcat网址应该是http://localhost:8080/yourWarName/contacts