我无法弄清楚如何做到这一点。我有一个带有颜色名称或十六进制代码(#ffffff)的字符数组,它没有将正确的RGB值返回给main,也没有超过"#"读取6个十六进制数字。我真的生锈了,大约一年没有编码,所以请批评你看到的任何东西。
/**readColor()
Converts the decimal values, color name or hex value read from
the input stream to the 3 byte RGB field
Returns the rgb values if successful. On error prints errmsg and
exits.
**/
color_t readColor(FILE *infile, char *errmsg)
{
int rc, red, green, blue;
char alpha[7] = {};
int i=0;
rc = fscanf(infile, "%d %d %d\n", &red, &green, &blue);
if(rc == 3){
if(red>=0 && red<=255 && green>=0 && green<=255 && blue>=0 && blue<=255){
return((color_t){red, green, blue});
}
}
if (rc != 0){
printf("%s", errmsg);
return((color_t){0,0,0});
}
fgets(alpha, 10, infile);
fputs(alpha);
i=0;
if(strcmp(alpha, "white")==0){
return((color_t){255, 255, 255 });
}
else if(strcmp(alpha, "red")==0){
return((color_t){255, 0, 0});
}
else if(strcmp(alpha, "blue")==0){
return((color_t){0, 0, 255});
}
else if(strcmp(alpha, "purple")==0){
return((color_t){128, 0, 255});
}
else if(strcmp(alpha, "black")==0){
return((color_t){0, 0, 0});
}
else if(strcmp(alpha, "green")==0){
return((color_t){0, 255, 0});
}
else if(strcmp(alpha, "orange")==0){
return((color_t){255, 128, 0});
}
else if(strcmp(alpha, "yellow")==0){
return((color_t){255, 255, 0});
}
else if(alpha[0] == "#"){
alpha++;
if(sscanf(alpha, "%2x%2x%2x", &red, &green, &blue)!= 3){
printf("%s", errmsg);
}
else{
return((color_t){red, green, blue});
}
}
else{
printf("%s", errmsg);
}
return((color_t){0, 0, 0});
}
答案 0 :(得分:1)
您可以使用%x
格式说明符来读取十六进制值。 0填充宽度为2,无需进行范围测试。 e.g。
int r, g, b;
if( 3 == scanf( "#%02x%02x%02x", &r, &g, &b ) )
{
printf( "Red : %3d (%02x)\n", r, r );
printf( "Green : %3d (%02x)\n", g, g );
printf( "Blue : %3d (%02x)\n", b, b );
}
答案 1 :(得分:0)
alpha[0] == "#"
^ ^
double quotes for string literal
应该是
alpha[0] == '#'
^ ^
single quotes for character literal
将单个字符与字符串文字进行比较是违反约束(感谢@AnT指出术语错误),编译器不应允许它。而是将单个字符与字符文字进行比较。