为什么我的php表单不起作用,我没有收到电子邮件

时间:2016-02-04 21:28:48

标签: php email

我有这个php形式:

        <form method="post" action="mailer.php" class="contact-form-map"> 
        <div class="row">
            <input type="text" name="name" id="name" placeholder="Your Name" required>
        </div>
        <div class="row">
            <input type="number" name="number" id="number" placeholder="Contact Number" required>
        </div>
        <div class="row">
            <textarea type="text" name="message" id="message" placeholder="Message" rows="6" cols="33" required></textarea>
        </div>
        <div class="row">
            <input type="submit" class="map-button" value="Send">
        </div>
        </form>

这是我的mailer.php

<?php 
if(isset($_POST['submit'])){

    $to = "lala.lal@gmail.com"; // info@computerrepairscroydon.co.uk

    $name = $_POST['name']; 

    $number = $_POST['number'];

    $subject = "Form submission - Contact";

    $message = $name . " " . " wrote the following:" . "\n\n" . $_POST['message'] . "\n\n" . " Contact number: " . $number ;

    $headers = "From:" . $name;

    mail($to,$subject,$message,$headers);

    echo "Mail Sent. Thank you " . $name . ", we will contact you shortly.";

    header("Location: index.html?success=1#form");

    }
?>

当我输入信息到de form并点击发送没有任何反应,但电子邮件没有发送,我不在我的Gmail上。 那是为什么?

2 个答案:

答案 0 :(得分:2)

您忘记将name =“submit”写入提交输入

<input type="submit" class="map-button" value="Send" name="submit">

这就是为什么代码“跳”到if isset $ _POST [“submit”]

答案 1 :(得分:0)

您需要在提交按钮中添加name =“submit”。

<input type="submit" class="map-button" value="Send" name="submit">