Question

我正在尝试通过控制台应用程序中的HttpWebRequest发送附件。经过几天的搜索和搜索互联网寻求一些可以理解的帮助，我提出了我认为来自this site的正确解决方案

虽然我认为我已正确完成所有操作，但我收到以下错误：

在遇到终止边界之前，Multipart流已结束。

问题：
我希望得到一些关于我收到的multipart错误的帮助/指导，以及协助附加XML文档的实际byte[]。

要求：

需要附加的数据文件是XML文件应该是MTOM Attachment。为了使它Mtom，我的理解是我需要确保messageEncoding <binding>中app.config元素的属性应具有值"Mtom"，这将按此编码。
根据业务要求（严格要求），我需要发送文件的byte[]，而不仅仅是内容本身。

网络请求方法

private static HttpWebRequest CreateWebRequest(SoapAction action)
{
    // Retrieve URL from Endpoint in the app.Config based on the action passed into the
    // method.
    string url = GetUrlAddress(action);

    if (url != null)
    {
        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);

        request.Headers.Add(HttpRequestHeader.AcceptEncoding, "gzip, deflate");
        request.Headers.Add(HttpRequestHeader.ContentEncoding, "gzip");
        request.Headers.Add("Content-Transfer-Encoding", "8bit");
        request.Headers.Add("SOAPAction", action.ToString());

        request.Method = "POST";

        request.Headers.Add("MIME-Version", "1.0");
        request.ContentType = "multipart/form-data; type=\"application/xop+xml;\" boundary=\"" + BoundaryMarker + "\"";

        request.ClientCertificates.Add(SecurityCertificate.CertificateObject);

        ServicePointManager.Expect100Continue = false;

        return request;
    }
    else
    {
        throw new NullReferenceException("Address for Endpoint could not be resolved.");
    }
}

提交请求的方法
根据我的this post，我相信我正在使用HttpWebRequest正确压缩GZip。

private static void SubmitRequest(HttpWebRequest request, XDocument soapXml, byte[] formXmlBytes, FileInfo fileToUpload)
{
    using (Stream requestStream = request.GetRequestStream())
    {
        using (GZipStream gz = new GZipStream(requestStream, CompressionMode.Compress, false))
        {
            soapXml.Save(gz);
            WriteToStream(gz, formXmlBytes, fileToUpload.Name);
        }
    }
}

用于将MIME信息和附件写入流

public static void WriteToStream(Stream stream, byte[] formData, string fileName)
    {
        // Write a new line to the stream.
        byte[] newLineBytes = Encoding.UTF8.GetBytes("\r\n");
        stream.Write(newLineBytes, 0, newLineBytes.Length);

        // Write the header to the stream.
        string header = String.Format(HeaderTemplate, BoundaryMarker, fileName, RequestContentID);
        byte[] headerBytes = Encoding.UTF8.GetBytes(header);
        stream.Write(headerBytes, 0, headerBytes.Length);

        // Write a new line to the stream.
        stream.Write(newLineBytes, 0, newLineBytes.Length);

        // Write the formData to the stream.
        stream.Write(formData, 0, formData.Length);

        // Write a new line to the stream.
        stream.Write(newLineBytes, 0, newLineBytes.Length);

        // Write the footer to the stream.
        byte[] boundaryFooterBytes = Encoding.UTF8.GetBytes("--" + BoundaryMarker + "--");
        stream.Write(boundaryFooterBytes, 0, boundaryFooterBytes.Length);
    }

Soap Body Snippet Element
通过使用Fiddler，我能够看到请求的实际情况。对我来说，似乎附件实际上是作为XML而不是（我认为会是）byte[]附加到请求中。

此后应该是附件的byte[]。目前，正在显示完整的XML文档。

Accept-Encoding: gzip, deflate
Content-Transfer-Encoding: 8bit
MIME-Version: 1.0
Content-Type: multipart/form-data; type="application/xop+xml;" boundary="--b73acdd180274cab985e4d697bfde428"
Content-Length: 582081
Connection: Keep-Alive

<?xml version="1.0" encoding="utf-8"?>
<soapenv:Envelope xmlns:soapenv="..." ...>
...
<soapenv:Body>
    <urn:Request version="1.0">
        <urn:FileAttachment>cid:b73acdd180274cab985e4d697bfde428</urn:FileAttachment>
    </urn:Request>
</soapenv:Body>
</soapenv:Envelope>
----b73acdd180274cab985e4d697bfde428
Content-Disposition: attachment; filename="test.xml"
Content-Type: text/xml
Content-Id: b73acdd180274cab985e4d697bfde428
<XML OF ATTACHMENT>
----b73acdd180274cab985e4d697bfde428--

通过SOAP HttpWebRequest发送附件

0 个答案: