Question

我目前正在尝试在unity3D中制作一款小型手机游戏，因为我总是听说使用instantiate / destroy是一种非常糟糕的方式（虽然我从来没有做过任何足够大的地方，这实际上成了问题）我决定尝试制作汇集系统。

我创建了一个脚本，用于处理两个单独列表中的所有池化对象。我可以通过从脚本本身调用方法成功地从池中生成一个对象，但问题是当我尝试从另一个脚本调用该方法时，它不起作用。通过我所做的不同尝试，我得到了空引用异常，或者得到了错误：

由于对象的当前状态，操作无效 System.Linq.Enumerable.First [GameObject]（IEnumerable`1 source）

我真的找不到其他人遇到这个问题。并且似乎相关的解决方案不起作用。主要问题也可能是..为什么会发生这种情况？

池脚本：

public class ObjectPool : MonoBehaviour {


    GameObject basicCell;
    GameObject basicFood;

    private Vector3 poolSpawnPos;

    [SerializeField]
    private int cellAmount;

    [SerializeField]
    private int foodAmount;

    List<GameObject> cellPool;
    List<GameObject> foodPool;

    GameObject foodManager;
    GameObject cellManager;
    // Use this for initialization
    void Awake () {

        foodManager = gameObject.transform.FindChild ("FoodPool").gameObject;
        cellManager = gameObject.transform.FindChild ("CellPool").gameObject;

        cellPool = new List<GameObject> (cellAmount);
        foodPool = new List<GameObject> (foodAmount);
        poolSpawnPos = new Vector3 (8000, 8000, 8000);
        basicFood = Resources.Load ("Food/BasicFood/BasicFood") as GameObject;
        basicCell = Resources.Load ("Cell/Cell") as GameObject;
        for (int i = 0; i < cellAmount; i++) {
            GameObject currentCell = Instantiate(basicCell, poolSpawnPos, Quaternion.identity) as GameObject;
            currentCell.transform.parent = cellManager.transform;
            currentCell.SetActive (false);
            cellPool.Add (currentCell);

        }

        for (int i = 0; i < foodAmount; i++){
            GameObject currentFood = Instantiate(basicFood, poolSpawnPos, Quaternion.identity) as GameObject;
            currentFood.transform.parent = foodManager.transform;
            currentFood.SetActive (false);
            foodPool.Add (currentFood);
        }
    }

    // Update is called once per frame
    void Update () {
        //if(foodPool.Count > 0)
        //  SpawnFood (new Vector3 (0, 0, 0));
    }

    public void SpawnFood(Vector3 spawnPosition)
    {
        GameObject selectedFood = null;
        selectedFood = foodPool.First();
        print (selectedFood);
        selectedFood.SetActive (true);
        foodPool.Remove (selectedFood);

        selectedFood.transform.parent = null;
        selectedFood.transform.position = spawnPosition;


        //set food Stats


    }


    public void KillFood(GameObject killedFood)
    {
        foodPool.Add (killedFood);
        killedFood.transform.position = poolSpawnPos;
        killedFood.transform.parent = foodManager.transform;
        killedFood.SetActive (false);

    }
}

我需要调用该方法的脚本：

public class FoodManager : MonoBehaviour {

    public ObjectPool pool;
    public int initialFoodNumber = 50;

    void Awake()
    {
        pool = GameObject.Find("ObjectPool").GetComponent<ObjectPool>();

        for (int i = 0; i <= initialFoodNumber; i++)
        {
            pool.SpawnFood(new Vector3(Random.Range(-40, 41), 0, Random.Range(-40, 41)));
        }
    }

}

Answer 1

您可以将Awake()中的FoodManager更改为Start()，以确保首先调用ObjectPool中的代码。

或者您可以显式设置这两个类的脚本执行顺序。这是通过转到Edit > Project Settings > Script Execution Order菜单并添加两个脚本ObjectPool排名高于FoodManager来完成的。 Source

Unity3D：当从其他类访问时，List返回null

1 个答案: