Question

如何让Python返回字符串中重复单词的位置？

E.g。 “猫坐在猫下面的垫子上”中的“猫”这个词在句子的第2和第11位。

Answer 1

您可以使用re.finditer查找字符串中所有出现的单词并启动索引：

import re

for word in set(sentence.split()):
    indexes = [w.start() for w in re.finditer(word, sentence)]
    print(word, len(indexes), indexes)

使用字典理解：

{word: [w.start() for w in re.finditer(word, sentence)] for word in sentence.split()}

Answer 2

这将返回一个字典，将句子中的每个单词（至少重复一次）映射到单词索引列表（不是字符索引）

from collections import defaultdict

sentence = "the cat sat on the mat which was below the cat"

def foo(mystr):
    sentence = mystr.lower().split()
    counter = defaultdict(list)
    for i in range(len(sentence)):
        counter[sentence[i]].append(i+1)

    new_dict = {}
    for k, v in counter.iteritems():
        if len(v) > 1:
            new_dict[k] = v

    return new_dict

print foo(sentence)

Answer 3

以下将采用输入句子，从句子中取出一个单词，然后在起始索引为1的列表中打印单词的位置（看起来像你想要的那样）来自你的代码）。

sentence = input("Enter a sentence, ").lower()
word = input("Enter a word from the sentence, ").lower()
words = sentence.split(' ')
positions = [ i+1 for i,w in enumerate(words) if w == word ]
print(positions)

Answer 4

我更喜欢简单，下面是我的代码：

convert.exe -page A4 test.png xc:white -gravity center -composite -format pdf -resize "595x842>" test.pdf

＆＃39;＆＃39;由句子中出现的所有单词列表组成。然后，我们迭代并匹配索引＆＃39; pos＆＃39;中出现的每个单词。用我们想要查找的单词（word_to_find），如果两个单词相同，那么我们打印pos的值，加上1。

希望这很简单，让你理解，它符合你的目的。

如果您希望使用上面的列表理解，那么：

sentence = input("Enter a sentence, ").lower()
word_to_find = input("Enter a word from the sentence, ").lower()
words = sentence.split()  ## Splits the string 'sentence' and returns a list of words in it. Split() method splits on default delimiters.

for pos in range(len(words)):
    if word_to_find == words[pos]:   ## words[pos] corresponds to the word present in the 'words' list at 'pos' index position.
        print (pos+1)

上述两种方式都相同，只是后面会给你一个清单。

Answer 5

positions= [] 

sentence= input("Enter the sentence please: ").lower() 

sentence=sentence.split( ) 

length=len(sentence))

word = input("Enter the word that you would like to search for please: ").lower() 

if word not in sentence: 
     print ("Error, '"+word+"' is not in this sentence.") 

else: 
     for x in range(0,length):
          if sentence[x]==word: #
               positions.append(x+1)
     print(word,"is at positions", positions)

Answer 6

s="hello fattie i'm a fattie too"
#this code is unsure but manageable
looking word= "fattie"
li=[]
for i in range(len(s)):
    if s.startswith(lw, i):
        print (i)
        space = s[:i].count(" ")
        hello = space+1
        print (hello)
        li.append(hello)
print(li)

如何在字符串中找到重复单词的位置 - Python

6 个答案: