python中的2D列表在每个列表中的相同位置更改值

时间:2016-02-04 15:48:10

标签: python list tic-tac-toe

def boardprint():
    array_board = board
    print(
" _ _ _\n"+
"|"+(array_board[0][0])+"|"+(array_board[0][1])+"|"+(array_board[0][2])+"|\n"+
"|_|_|_|\n"+
"|"+(array_board[1][0])+"|"+(array_board[1][1])+"|"+(array_board[1][2])+"|\n"+
"|_|_|_|\n"+
"|"+(array_board[2][0])+"|"+(array_board[2][1])+"|"+(array_board[2][2])+"|\n"+
"|_|_|_|\n"
        )




board=[[" "]*3]*3
move=0


boardprint()
board_full=False
won=False
while (board_full!=True and won!=True):
    move+=1
    move_success=False
    while (move_success==False):
        row_position=int(input("In which row would you like to place a cross?"))
        col_position=int(input("In which column would you like to place a cross?"))
        if (board[col_position][row_position]==" "):
            (board[col_position][row_position])="x"
            move_success=True
        else:
            print("Try again, that position is full")
        boardprint()
    if (move>=9):
        board_full=True
    move+=1
    move_success=False
    while (move_success == False):
        row_position=int(input("In which row would you like to place a nought?"))
        col_position=int(input("In which column would you like to place a nought?"))
        if (board[col_position][row_position]==" "):
            board[col_position][row_position]="o"
            move_success=True
        else:
             print("Try again, that position is full")
        boardprint()

这应该是一个井字游戏。然而,当用户在棋盘中输入他们想要的位置时,它会用整个列填充整个列,忽略行。我知道一维列表会更容易但是我的Comp Sci老师要我使用2D列表并且他没有& #39;不知道为什么会这样做。

1 个答案:

答案 0 :(得分:0)

更换

board = [[" "]*3]*3

from copy import deepcopy
board = [deepcopy([' ' for x in range(3)]) for x in range(3)]

应该解决您的问题,但是您的原始问题源于一些深层复制和浅层复制问题,并且您应该真正红色Dan的链接,因为它解决了您的确切问题。

虽然您可以考虑使用用户输入的值 - 1表示他们打算制作的tic tac 2标记的位置。例如,如果我输入1,1,我可能想在此处标记:

 _ _ _
|X| | |
|_|_|_|
| | | |
|_|_|_|
| | | |
|_|_|_|

并不一定在这里:

 _ _ _
| | | |
|_|_|_|
| |x| |
|_|_|_|
| | | |
|_|_|_|
但是,这只是我,你的方式很好。