Question

这是我正在操作的单个表的片段。该表包含总共15个不同的符号，每天跨越3年（CurrDate）和大约370分钟（PRMinute）。我正在尝试一个查询，它会显示每个符号的最低值，每天显示低点（PRMinute）发生的低点。

Symbol  CurrDate    PRMinute    PROpen    PRHigh    PRLow   PRClose
SLV     2013-07-09  1           18.55     18.56     18.55   18.555
TLT     2013-07-09  1           107.45    107.45    107.45  107.45
UCO     2013-07-09  1           34.10     34.10     34.10   34.10
!COMP   2013-07-10  1           3502.11   3503.41   3502.00 3503.17
!DJI    2013-07-10  1           15298.03  15315.86  15297.07
!GSPC   2013-07-10  1           1651.56   1652.21   1651.56 1652.09 0
!RUT    2013-07-10  1           1017.69   1017.87   1017.69 1017.87 0

CREATE TABLE [dbo].[IntradayInput](
    [Symbol] [varchar](10) NULL,
    [CurrDate] [date] NULL,
    [PRMinute] [smallint] NULL,
    [PROpen] [money] NULL,
    [PRHigh] [money] NULL,
    [PRLow] [money] NULL,
    [PRClose] [money] NULL,
    [PRVol] [bigint] NULL
) ON [PRIMARY]

Answer 1

在SQL Server中执行此操作的规范方法是使用row_number()：

select ii.*
from (select ii.*,
             row_number() over (partition by symbol, currdate 
                                order by prlow asc end) as seqnum
      from IntradayInput ii
     ) ii
where seqnum = 1;

这假定prlow包含有关最低值的信息。没有名为value的列。

Answer 2

这与戈登的答案类似，但不使用排名功能。

SELECT [Symbol], [CurrDate], MIN([PRLow]) AS Min_PRLow
  , (SELECT MIN([PRMinute]) FROM [IntradayInput] mi 
       WHERE mi.[Symbol]=i.[Symbol] AND mi.[CurrDate]=i.[CurrDate] 
         AND mi.PRLow=MIN(i.[PRLow])) AS PRMinute
  FROM [IntradayInput] i GROUP BY [Symbol],[CurrDate]

SQL Server - 在符号

2 个答案: