Question

我有一张表app_user：

CREATE TABLE app_user (
  id            BINARY(16) NOT NULL,
  email_address VARCHAR(255),
  password      VARCHAR(255),
  username      VARCHAR(255),
  role          VARCHAR(255),
  credits       INTEGER,
  PRIMARY KEY (id)
);

我还有一个表played_game_round，它使用外键约束引用id的{{1}}：

app_user

如果我在CREATE TABLE played_game_round ( id BINARY(16) NOT NULL, game_shots LONGTEXT, game_picture_set_id BINARY(16), user_id BINARY(255), PRIMARY KEY (id) );表中执行INSERT，则会出现外键违规：

played_game_round

但我确信这是正确的。

这是Cannot add or update a child row: a foreign key constraint fails (`myappdb`.`played_game_round`, CONSTRAINT `FK_67s32eu4d5d1m18ub5brp5fk2` FOREIGN KEY (`user_id`) REFERENCES `app_user` (`id`))显示的内容：

show engine innodb status

我已经从我的Java代码进行了测试，并且我也在MySQL控制台中使用https://gist.github.com/damienb/159151中的------------------------ LATEST FOREIGN KEY ERROR ------------------------ 2016-02-04 15:05:52 0x700000d51000 Transaction: TRANSACTION 10052, ACTIVE 0 sec inserting mysql tables in use 2, locked 2 6 lock struct(s), heap size 1136, 3 row lock(s), undo log entries 1 MySQL thread id 3, OS thread handle 123145316274176, query id 1698 localhost 127.0.0.1 root INSERT INTO myappdb.played_game_round (game_picture_set_id, game_shots, user_id, id) VALUES (uuid_to_bin("f63b99f0-9f33-46dc-8a30-e716394f44e7"), "bla", (SELECT id from app_user where id = uuid_to_bin("9d025d10-4fe1-4af1-a361-e91852f00733")), uuid_to_bin("37f3ec14-c65c-4603-b1d2-04bb801b24f1")) Foreign key constraint fails for table `myappdb`.`played_game_round`: , CONSTRAINT `FK_67s32eu4d5d1m18ub5brp5fk2` FOREIGN KEY (`user_id`) REFERENCES `app_user` (`id`) Trying to add in child table, in index FK_67s32eu4d5d1m18ub5brp5fk2 tuple: DATA TUPLE: 2 fields; 0: len 255; hex 9d025d104fe14af1a361e91852f007330000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000; asc ] O J a R 3 ;; 1: len 16; hex 37f3ec14c65c4603b1d204bb801b24f1; asc 7 \F $ ;; But in parent table `myappdb`.`app_user`, in index PRIMARY, the closest match we can find is record: PHYSICAL RECORD: n_fields 8; compact format; info bits 0 0: len 16; hex 9d025d104fe14af1a361e91852f00733; asc ] O J a R 3;; 1: len 6; hex 000000002722; asc '";; 2: len 7; hex ba0000012e0110; asc . ;; 3: len 16; hex 706c6179657240676d61696c2e636f6d; asc player@gmail.com;; 4: len 6; hex 706c61796572; asc player;; 5: len 6; hex 706c61796572; asc player;; 6: len 6; hex 504c41594552; asc PLAYER;; 7: len 4; hex 80000032; asc 2;;函数重现了它。

可能是什么问题？

Answer 1

在搜索了几个小时后发现自己4分钟后发现自己：

user_id列定义为BINARY(255)，但BINARY(16)列应与id表的app_user列相同。

使用UUID插入时MySQL外键失败

1 个答案: