Question

您好我试图将对象列表绑定到datagridview 绑定现有列表（Of is正在运行但我尝试添加或删除对象，我的dgv不会更新。

    Public Class Form1
    Dim lt As New List(Of Test)
    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        lt.Add(New Test("Mac", 2200))
        lt.Add(New Test("PC", 1100))
        dgv.DataSource = lt

        lt.Add(New Test("Android", 3300)) 'This line won't appear in the dgv
    End Sub
End Class

Public Class Test
    Public Sub New(ByVal name As String, ByVal cost As String)
        _name = name
        _cost = cost
    End Sub
    Private _name As String
    Public Property Name() As String
        Get
            Return _name
        End Get
        Set(ByVal value As String)
            _name = value
        End Set
    End Property
    Private _cost As String
    Public Property Cost() As String
        Get
            Return _cost
        End Get
        Set(ByVal value As String)
            _cost = value
        End Set
    End Property
End Class

如何在dgv中添加，删除或更改值到列表中？

NoiseBe

Answer 1

更改此行：

Dim lt As New List(Of Test)

要：

Imports System.ComponentModel
...
Private lt As New BindingList(Of Test)

当收集内容发生变化时，您应该使用BindingList(Of T)。此集合具有与之关联的事件，使其了解列表内容的更改。

如果除了列表内容之外，列表 items 将会更改（如Test.Name），您还应该在类本身上实现INotifyPropertyChanged

另一种方法：

dgv.DataSource = Nothing
lt.Add(New Test("Android", 3300))
dgv.DataSource = lt

这会“重置”DataSource，以便显示新内容。但是，这意味着其他几件事情会像所选项目一样重置;如果您绑定到List / Combo控件，则还必须重置ValueMember和DisplayMember属性。

将行添加到类绑定的datagridview

1 个答案: